问题
If you run the following code in the Groovy console it prints "8"
class F {
private final Integer val = 2
def set(v) {val = v}
def print() {println val}
}
def f = new F()
f.set(8)
f.print()
In Java this code wouldn't compile because you can't assign a final reference after the constructor has run. I know that for properties, final indicates that the property can't be changed outside the class, but what does it mean to mark a private field final?
Thanks, Don
回答1:
It looks like this might be a Groovy bug:
- https://issues.apache.org/jira/browse/GROOVY-1628
- https://issues.apache.org/jira/browse/GROOVY-2752
I wouldn't think that val should be assignable after initialization.
来源:https://stackoverflow.com/questions/1652133/what-does-final-mean-in-groovy