Getting the user home path in application.properties in Spring Boot

问题

This should be a quite straight forward task, but after doing quite a bit of research I'm finding it hard to find any way to do this.

I just want to create a log file in the current user's home directory. According to the Official Documentation the variables I should modify are logging.file and logging.path. But how do I get the value of the user-home into the logging.path?

I have tried setting it up like:

logging.path=#{systemProperties['user.home']}

but without any success.

回答1:

If you use Linux or Mac OS, you can use logging.path=${HOME}/logs.

${HOME} is substituted by the environment variable HOME.

回答2:

I believe I have solved the problem. The log file in question was actually being generated in the class path only when run from the IDE (Eclipse Luna FYI). Later on when I made a jar file and ran that, the log file was being generated in the right location as specified in the application.properties file. I still have no clue to why it was generated in the class path when I ran it from Eclipse.

回答3:

I faced the same Issue in development environment so I tried another approach. If you have read official document It also states you can give custom configurations. And logging.path will use as a default if no custom configuration provided IMO.

I want to use log4j2 so I need custom pattern and other stuff. For that I actually put the log4j2.xml configuration file into the class-path. Look at my xml conf file for more details which actually worked in both dev and production.

<?xml version="1.0" encoding="UTF-8"?>
<configuration monitorInterval="30">
    <properties>
        <property name="app.name">my-app</property>
        <property name="pattern">%d{ISO8601} %-5p %c - %m%n</property>
    </properties>
    <appenders>
        <Console name="console" target="SYSTEM_OUT">
            <PatternLayout pattern="${pattern}"/>
        </Console>

        <RollingRandomAccessFile name="my_app" append="false" fileName="${sys:user.home}\.${app.name}\logs\${app.name}.log"
                 filePattern="${sys:user.home}\.${app.name}\logs\$${date:yyyy-MM}/${app.name}-%d{yyyy-MM-dd}-%i.log.zip">
            <PatternLayout>
                <pattern>${pattern}</pattern>
            </PatternLayout>
            <Policies>
                <SizeBasedTriggeringPolicy size="5 MB"/>
            </Policies>
            <DefaultRolloverStrategy max="10"/>
        </RollingRandomAccessFile>
    </appenders>
    <loggers>
        <root level="INFO">
            <AppenderRef ref="console"/> <!-- To console -->
            <AppenderRef ref="my_app"/>
        </root>

        <AsyncLogger name="com.rameysoft.streamline.main" additivity="FALSE" level="DEBUG">
            <AppenderRef ref="console"/>
            <AppenderRef ref="my_app"/>
        </AsyncLogger>
    </loggers>
</configuration>

来源：https://stackoverflow.com/questions/30432473/getting-the-user-home-path-in-application-properties-in-spring-boot

标签

Spring

logging

spring-boot

spring-el