问题
Here is the code that I was trying on my workstation.
class Program
{
public static volatile bool status = true;
public static void Main()
{
Thread FirstStart = new Thread(threadrun);
FirstStart.Start();
Thread.Sleep(200);
Thread thirdstart = new Thread(threadrun2);
thirdstart.Start();
Console.ReadLine();
}
static void threadrun()
{
while (status)
{
Console.WriteLine("Waiting..");
}
}
static void threadrun2()
{
status = false;
Console.WriteLine("the bool value is now made FALSE");
}
}
As you can see I have fired three threads in Main. Then using breakpoints I tracked the threads. My initial conception was all the three threads will be fired simultaneously, but my breakpoint flow showed that the thread-execution-flow followed one after other (and so was the output format i.e. Top to bottom execution of threads). Guys why is that happening ?
Additionally I tried to run the same program without using the volatile keyword in declaration, and I found no change in program execution. I doubt the volatile keyword is of no practical live use. Am I going wrong somewhere?
回答1:
Ok I will try to explain a very long story as short as possible:
Number 1: Trying to inspect the behavior of threads with the debugger is as useful as repeatedly running a multithreaded program and concluding that it works fine because out of 100 tests none failed: WRONG! Threads behave in a completely nondeterministic (some would say random) way and you need different methods to make sure such a program will run correctly.
Number 2: The use of volatile will become clear once you remove it and then run your program in Debug mode and then switch to Release mode. I think you will have a surprise... What happens in Release mode is that the compiler will optimize code (this includes reordering instructions and caching of values). Now, if your two threads run on different processor cores, then the core executing the thread that is checking for the value of status will cache its value instead of repeatedly checking for it. The other thread will set it but the first one will never see the change: deadlock! volatile prevents this kind of situation from occurring.
In a sense, volatile is a guard in case the code does not actually (and most likely will not) run as you think it will in a multithreaded scenario.
回答2:
Your method of thinking is flawed.
The very nature of threading related issues is that they're non-deterministic. This means that what you have observed is potentially no indicator of what may happen in the future.
This is the very nature of why multithreaded programming is "hard." It often defies ad hoc testing, or even most unit testing. The only way to do it effectively is to understand your entire software and hardware stack, and diagram every possible occurrence through use of state machines.
In summary, threaded programming is not about what you've seen happen, it's about what might possibly happen, no matter how improbable.
回答3:
The fact that your simple code doesn't behave dirrefently with volatile doesn't mean anything. Your code is too simple and has nothing to do with volatile. You need to write very computation-intensive code to create a clearly visible memory race condition.
Also, volatile keyword may be useful on other platforms than x86/x64 with other memory models. (I mean like for example Itanium.)
Joe Duffy wrote interesting information about volatile on his blog. I strongly recommend to read it.
回答4:
Then using breakpoints I tracked the threads. My initial conception was all the three threads will be fired simultaneously, but my breakpoint flow showed that the thread-execution-flow followed one after other (and so was the output format i.e. Top to bottom execution of threads). Guys why is that happening?
The debugger is temporarily suspending the threads to make it easier to debug.
I doubt the volatile keyword is of no practical live use. Am I going wrong somewhere?
The Console.WriteLine calls are very likely fixing masking the problem. They are most likely generating the necessary memory barrier for you implicitly. Here is a really simple snippet of code that demonstrates that there is, in fact, a problem when volatile is not used to declare the stop variable.
Compile the following code with the Release configuration and run it outside of the debugger.
class Program
{
static bool stop = false;
public static void Main(string[] args)
{
var t = new Thread(() =>
{
Console.WriteLine("thread begin");
bool toggle = false;
while (!stop)
{
toggle = !toggle;
}
Console.WriteLine("thread end");
});
t.Start();
Thread.Sleep(1000);
stop = true;
Console.WriteLine("stop = true");
Console.WriteLine("waiting...");
t.Join();
}
}
来源:https://stackoverflow.com/questions/8539212/do-we-really-need-volatile-keyword-in-c