how to get date difference in xslt

问题

My Schema is :

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:datetime="http://exslt.org/dates-and-times" xmlns:fn="http://www.w3.org/2005/xpath-functions">

I am trying to get difference between two date .

No clue.

回答1:

Example to get date difference is:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema">

 <xsl:param name="currentDate" select="current-date()"/>
  <xsl:param name="yesterdayDate" select="'2013-05-12'"/>

  <xsl:template match="/">
    <xsl:value-of select="$currentDate - xs:date($yesterdayDate)"/><!-- Result in duration  -->
  </xsl:template>

</xsl:stylesheet>

来源：https://stackoverflow.com/questions/16521746/how-to-get-date-difference-in-xslt