问题
I have put together a code to send emails to multiple recipients. However each recipient receives all mails instead of his own.
Dataframe:
email content
mark@gmail.com Hi Mark, bla bla
eve@gmail.com Hi Eve, bla bla
john@gmail.com Hi, John bla bla
for content in df['content']:
for email in df['email']:
message = MIMEMultipart()
message['Subject'] = "Subject"
message['From'] = 'my email'
message['Reply-to'] = 'my email'
message['To'] = '{}'.format(email)
text = MIMEText(mail)
message.attach(text)
server = smtplib.SMTP ('smtp.gmail.com',587)
server.ehlo()
server.starttls()
server.login(login, password)
server.sendmail(message['From'], message['To'], message.as_string())
server.quit()
回答1:
Try this:
df = {
'content': ['test1', 'test2', 'test3'],
'email': ['mail1@mail.com', 'mail2@mail.com', 'mail3@mail.com']
}
x = 0
for email in df['email']:
print(email)
print(df["content"][x]+"\n")
x+=1
回答2:
Just zip
columns together and omit one loop:
for email, content in zip(df['email'], df['content']):
message = MIMEMultipart()
message['Subject'] = "Subject"
message['From'] = 'my email'
message['Reply-to'] = 'my email'
message['To'] = '{}'.format(email)
text = MIMEText(mail)
message.attach(text)
server = smtplib.SMTP ('smtp.gmail.com',587)
server.ehlo()
server.starttls()
server.login(login, password)
server.sendmail(message['From'], message['To'], message.as_string())
server.quit()
回答3:
I was iterating it twice. Instead of using 2 for loops, the correct way to iterate through out DataFrame is using
Instead of this:
for content in df['content']:
for email in df['email']:
Use this:
for c in df.itertuples():
message = MIMEMultipart()
message['To'] = '{}'.format(c[0])
text = MIMEText(c[1])
message.attach(text)
来源:https://stackoverflow.com/questions/50774697/send-individual-emails-to-multiple-recipients