Django - Parse JSONP (Json with Padding)

问题

I'm using JSONP to send data from otherdomain.com to mydomain.com

However, I got errer when I tried to parse JSONP data in django controller (views.py).

Here is my code.

Javascript in mydomain.com client page

jsonData = {
    'foo': 'bar',
}

$.ajax({
    url: 'http://otherdomain.com/end_point/',
    type: 'GET',
    contentType: 'application/json; charset=utf-8',
    data: jsonData,
    dataType : 'jsonp',
    jsonp : 'callback'
});

Django controller (views.py) in mydomain.com

from django.http import JsonResponse
import json

def decode_jsonp(request):

    if 'callback' in request.GET:
        json_object = json.loads(request.body) # Raise error
        json_object = json.dumps(request.body) # Do not raise error but returns nothing
        json_object = json.loads(json.dumps(request.body)) # Raise error

        foo = json_object['foo']

    return JsonResponse({'foo': foo})

I don't know what should I substitue for json_object = json.loads(request.body)

回答1:

A JSONP object has parentheses around it and a callback. But Python's json module doesn't recognise a JSONP object. So, you'll have to first convert it to JSON object by removing the surrounding parentheses and the callback name.

Example

>>> data = 'callback({"key": "val"})' # a common JSONP object
>>>
>>> json.loads(data)
# raises ValueError
>>>
>>> data_json = data.split("(", 1)[1].strip(")") # convert to json
>>> data_json
'{"key": "val"}' 
>>>
>>> json.loads(data_json)
# success

回答2:

Thanks for @xyres. Here is solution.

def decode_jsonp(request):

    if 'callback' in request.GET:
        query_string = request.GET.urlencode()
        json_object = {x.split('=')[0]:str(x.split('=')[1]) for x in query_string.split("&")}

        foo = json_object['foo']

    return JsonResponse({'foo': foo})

来源：https://stackoverflow.com/questions/30554522/django-parse-jsonp-json-with-padding

标签

python

django

jsonp