问题
Let's say I have a model for my email address book:
class contact(db.Model):
email = db.EmailProperty()
image = #Hmm.
My contacts' images will be stored in the Blobstore, and served at various sizes.
So, should I use a db.ReferenceProperty(BlobInfo) such that I can serve it by doing:
get_serving_url(alice.image.key, size=x)
Or should I use a db.StringProperty so that I don't have to make the second read in order to get the key:
get_serving_url(alice.image, size=x)
Or should I use a db.LinkProperty for the base URL, post-fixing the size needed:
alice.image+'=sx'
I don't foresee needing anything other than the key, so I think the second is better than the first.
Though I am unsure if the third is best because I am unsure whether it is as efficient as creating a unique URL, which can be cached to avoid repeatedly generating the same thumbnail - or is this handled automagically in both cases?
回答1:
After some experimentation, I think I can answer my own question.
Well, sort of. It turns out that the answer is "this wasn't a real problem to begin with".
While get_serving_url() gives the impression that something fancy is being done, actually the 'serving URL' is nothing more than a post-fixing of the supplied BlobKey.
What's more, supplying size=x merely appends =sx - there's nothing special, more or less efficient, about doing it this way. My second and third options, really are identical.
Finally, the __BlobInfo__ entity kind uses the BlobKey as its key name, so it is also easy to access from the other.
I have decided to use, and would suggest to anyone with the same dilemma, my third option:
imgBlob = db.LinkProperty()
It is then easy to:
- append any resizing/cropping requirements
- give a default value/make required without overloading
put()
来源：https://stackoverflow.com/questions/25191382/best-way-to-link-datastore-entity-to-its-blobstore-image