How to simplify Q promise example

问题

I was working on a simple application that makes sequential ajax calls, passing result of first call into the next one.

Of course I don't want to go into the callback hell, and therefore look into Promises/A+ spec example and Q library.

I have prepared an async function that should result in what I want. But I want an insight on how I can simplify the Sequential promise passing.

For now I am still reading on how to best work with promises and deferred objects, so forgive me for the very naive code.

So now I am looking at two things:

the way to simplify the sequencing of promises (that depend on one another as in my case)

suggestions

var modifyableObject = {
    toProcess : ["one", "two", "three", "four", "five"]
}


function returnsDeferredResults(someResult) {

    var deferred = Q.defer();

    // my async function (setTimeout for now will do, $.ajax() later)
    setTimeout(function () {

        var nextResult = (someResult || " Initial_Blank_Value ") + "..." + modifyableObject.toProcess[0]; 

        modifyableObject.toProcess = modifyableObject.toProcess.splice(1);

        console.log("New Tick Result: ", nextResult, "Array: ", modifyableObject.toProcess);

        deferred.resolve( nextResult);

    }, 200);

    return deferred.promise;
}


//$("#test_promise").click(function () {

    function getDeferredResult(prevResult) {
        return returnsDeferredResults(prevResult);
    }

    var prevResult = getDeferredResult();

    var nextTick = "";

    for (var i = modifyableObject.toProcess.length; i > 1; i --) {

        if (nextTick) 
            nextTick = nextTick.then(getDeferredResult);
        else 
            nextTick = prevResult.then(getDeferredResult);
    }

    //nextTick.fin(function(){ ...});

//});



/*
New Tick Result:   Initial_Blank_Value ...one           Array:  ["two", "three", "four", "five"]
New Tick Result:   Initial_Blank_Value ...one...two            Array:  ["three", "four", "five"]
New Tick Result:   Initial_Blank_Value ...one...two...three             Array:  ["four", "five"] 
New Tick Result:   Initial_Blank_Value ...one...two...three...four              Array:  ["five"]
New Tick Result:   Initial_Blank_Value ...one...two...three...four...five             Array:  [] 
*/

Thank you everyone in advance!

回答1:

You can simplify your loop by combining the two variables:

var nextTick = getDeferredResult();

for (var i = modifyableObject.toProcess.length; i > 1; i --) {
    nextTick = nextTick.then(getDeferredResult);
}

Or,

return modifyableObject.toProcess.reduce(function(promise, item) {
    return promise.then(getDeferredResult);
}, Q.resolve());

You can simplify your function too:

return Q.delay(200).then(function) { 
    return "..." + modifyableObject.toProcess.shift();
});

jQuery AJAX also returns a promise, which Q is compatible with (in recent versions of jQuery)

You can then combine the two improvements by passing each item to the function:

return modifyableObject.toProcess.reduce(function(promise, item) {
    return promise.then(processItem.bind(null, item));
}, Q.resolve());

function processItem(item) {
    return Q.delay(200).then(function) { 
        return "..." + modifyableObject.toProcess.shift();
    });
}

来源：https://stackoverflow.com/questions/17452460/how-to-simplify-q-promise-example

标签

javascript

promise

deferred