问题
The program I am working on needs to pause and ask the user for input and if there is none, move on with the program. I think it would look something like this:
import time
...[code to run before break]...
if input in time.sleep(5):
[break out of normal code]
else:
[return to normal code]
[code to run after break]...
Any thoughts?
EDIT: Didn't think about this when I asked but I am running Windows (8.1).
回答1:
Bit of a quick-and-dirty hack, but effective. The following waits for user input for 5 seconds or until input is received, whichever happens first.
from datetime import datetime, timedelta
import os
import signal
import threading
import time
waiting = False
def wait_and_kill(timeout):
elapsed = timedelta(0)
while elapsed.total_seconds() < timeout and waiting:
start = datetime.now()
time.sleep(0.1)
elapsed += datetime.now() - start
if waiting:
os.kill(os.getpid(), signal.SIGINT)
try:
t = threading.Thread(target=wait_and_kill, args=(5,))
waiting = True
t.start()
raw = raw_input('> ')
waiting = False
except KeyboardInterrupt:
pass
来源：https://stackoverflow.com/questions/28423884/asking-a-user-for-input-only-for-a-limited-amount-of-time-in-python