PHP - Concatenating two variables

问题

I'm a newbie stumped on the following. If I'm including an external file on a page that contains the following variable:

$blurb_78 = "Lorem ipsum dolor.";

How can I echo $blurb_78 on the local page? (where the 78 part is a generated article ID set to a variable labeled, $id)

The following doesn't work:

echo $blurb_.$id;

Thanks much for your help.

回答1:

I think you mean a variable variable name like it is mentioned at the Variable variables page on the PHP site. In your case this should work fine:

echo ${'blurb_'.$id}; 

But I highly doubt your approach on this one.

回答2:

Try making an array:

$blurb = array();

$blurb[78] = "Lorem ipsum";

echo $blurb[$id];

回答3:

You should use an associative array instead of variables in your case.

Check this article in PHP official documentation:

• http://php.net/manual/es/language.types.array.php

回答4:

This is your answer:

 echo '$blurb_'.$id;

Still, an associative array is the way to go.

回答5:

Try

<?php
$blurb_78 = 'Lorem ipsum dolor.';
$id = 78;
echo ${'blurb_'.$id};
?>

回答6:

This should work:

echo ${'blurb_'.$id}

回答7:

echo ${'blurb_'.$id};

Demo

Read more on the variable variables article.

来源：https://stackoverflow.com/questions/7648688/php-concatenating-two-variables