问题
I have a form (commonStuff) cloned this way (and an html page, designed in jquery mobile, where the form appears multiple times, cloned):
var commonClone = commonStuff.cloneNode(true);
and this function
function renameNodes(node) {
var i;
if (node.length) {
for (i = 0; i < node.length; i += 1) {
renameNodes(node[i]);
}
} else {
// rename any form-related elements
if (typeof node.form !== 'undefined') {
node.id = currentPrefix + '_' + node.id;
node.name = currentPrefix + '_' + node.name;
// This assumes that form elements do not have child form elements!
} else if (node.children) {
renameNodes(node.children);
}
}
}
which add a prefix 'form1_', 'form_2' (the currentPrefix) to id and names of any element in the form and is applied to commonClone (and so recursively to his sons).
renameNodes(commonClone);
It work perfectly in case of text inputs like
<div data-role="fieldcontain" class="ui-field-contain ui-body ui-br">
<label for="foo" class="ui-input-text">Age:</label>
<input type="text" name="age" id="age" value="" class="ui-input-text ui-body-c ui-corner-all ui-shadow-inset">
</div>
But it fails on radio buttons like
<div data-role="fieldcontain">
<fieldset data-role="controlgroup" data-type="horizontal">
<legend>Address:</legend>
<input type="radio" name="radio-address" id="radio-address_female" value="1" checked="checked" />
<label for="radio-address_female">Address 1</label>
<input type="radio" name="radio-address" id="radio-address_male" value="2" />
<label for="radio-address_male">Address 2</label>
</fieldset>
</div>
applying the renaming to the outer divs like 'fieldcontain' and 'controlgroup'. It works if i remove those two divs but the graphical effect is unacceptable...
As far as now, i got the problem is in the last 'else if' block for it doesn't care of siblings, but I don't really know how to fix this. Any idea?
EDIT: This code comes from this answer How to create a tabbed html form with a common div
回答1:
As you use jQuery mobile, jQuery will be available. I hope this code will point you in the right direction:
var i = 0;
$("form").each(function() {
$(this).find("input, select").each(function() {
$(this).attr("id", "form" + i + "_" + $(this).attr("id"));
$(this).attr("name", "form" + i + "_" + $(this).attr("name"));
});
$(this).find("label").each(function() {
$(this).attr("for", "form" + i + "_" + $(this).attr("for"));
});
i++;
});
EDIT:
I understand your current approach fails with labels. Consider to wrap your input elements inside the label tag. In that case, you won't need the for-attribute. This is in accordance with the docs: http://api.jquerymobile.com/checkboxradio/
Consider this:
HTML
<form>
<div data-role="fieldcontain">
<fieldset data-role="controlgroup" data-type="horizontal">
<legend>Address:</legend>
<label><input type="radio" name="radio-address" id="radio-address_female" value="1" checked="checked" />Address 1</label>
<label><input type="radio" name="radio-address" id="radio-address_male" value="2" />Address 2</label>
</fieldset>
</div>
<div data-role="fieldcontain" class="ui-field-contain ui-body ui-br">
<label><input type="text" name="age" id="age" value="" class="ui-input-text ui-body-c ui-corner-all ui-shadow-inset">Age:</label>
</div>
</form>
jQuery
var i = 0, currentPrefix = "form";
$("form").each(function() {
$(this).find("input, select").each(function() {
$(this).attr("id", currentPrefix + i + "_" + $(this).attr("id"));
$(this).attr("name", currentPrefix + i + "_" + $(this).attr("name"));
});
i++;
});
Workin fiddle: https://jsfiddle.net/EliteSystemer/8sx6rnwo/
回答2:
Truly, this is far from elegant, but a solution, anyway. In any node, this searches manually for input and labels, changing id, names and 'for' attribute in case of labels.
function renameNodes(node) {
var i;
if (node.length) {
for (i = 0; i < node.length; i += 1) {
renameNodes(node[i]);
}
} else {
// rename any form-related elements
if (typeof node.form !== 'undefined') {
node.id = currentPrefix + '_' + node.id;
node.name = currentPrefix + '_' + node.name;
var inputs = node.getElementsByTagName('input');
for (i = 0; i < inputs.length; ++i) {
inputs[i].id = currentPrefix + '_' + inputs[i].id;
inputs[i].name = currentPrefix + '_' + inputs[i].name;
}
var labels = node.getElementsByTagName('label');
for (i = 0; i < labels.length; ++i) {
labels[i].setAttribute('for', currentPrefix + '_' + labels[i].getAttribute("for"));
}
} else if (node.children) {
renameNodes(node.children);
}
}
}
来源:https://stackoverflow.com/questions/37789037/how-to-rename-all-id-in-a-cloned-form-javascript