问题
I have a route in my express app, which is supposed to do the following:
- Get some data from outside (OK)
- Show a HTML page with socket.io listening for messages (OK)
- Perform some calculations, which take a long time
- Send a message trough socket.io after each one one completed (OK)
- When all calculations are completed, show a result page (problem)
So, a simplified version of my code is:
module.exports = function(io) { // This is so I can use socket.io inside the route
var express = require('express');
var router = express.Router();
[... and other required]
router.post('/', function(req, res, next) {
res.render('loading'); // This renders the template which holds accepts and renders socket.io messages
pefromCalculaton();
sendSocketIOMessage();
session.data = resultData; // I get the result of all calculations and put that in the session. It's a quick fix, don't judge, I've got no presistancy in my project as for now...
res.redirect('results'); // And here I'd like to go to the other route, which will display the data, getting it from the session.
});
return router;
}
Since this doesn't work, I am probably trying to do something really stupid here. But what I actually want to do is:
- Perform calculations
- While performing the calculations, update progress using sockets
- When calculation is done, render a template, showing all the results.
回答1:
Well, my friend, as you know that one can't send two responses from within one request. So here is what you need to do.
module.exports = function(io) { // This is so I can use socket.io inside the route
var express = require('express');
var router = express.Router();
[... and other required]
router.post('/', function(req, res, next) {
var taskId = (new Date()).getTime(); //timestamp to get unique task id.
res.render('loading');
startCalculations(function(progressIndicator){ //progress callback
io.emit('progress',progressIndicator);
},function(result){ // Finish callback
session[taskId] = result;
io.emit('finish',{ taskid: taskId });
});
});
router.get('/result:taskId', function(req, res, next) {
var result = session[req.params.taskId];
if(!result)
{
//Result already consumed!
res.render('expired');
return;
}
delete session[req.params.taskId];
res.render('result', {result: result});
});
//progress callback will be called when we want to report progress
//done callback indicates our results are ready.
function startCalculations(progress, done){
//This is just a stupid piece of code, just to emulate loading.
//Your awesome async code will replace this
//In your case it will not be a loop and there will be a callback
//To signal finish.
var result = 0;
for(i = 0; i < 100; i++)
{
result = result + i;
//Simulate progress
progress(i);
}
//Simulate finish -- result has 0 to 99 all added up ;)
done(result);
}
return router;
}
Now on the html front you can have ...
this is how your
loading
view would look like.
<script src="/socket.io/socket.io.js"></script>
<script src="http://code.jquery.com/jquery-1.11.1.js"></script>
<script>
var socket = io();
//Init code.
socket.on('progress', function(progressIndicator){
//Your jquery mojo to show progress
displayProgress(progressIndicator);
});
socket.on('finish', function(task){
//Redirect to result page from frontend (you were trying to do
//on backend -- node.js)
window.location.href = "/result/" + task.taskId;
//OR
//window.location.replace("/result/" + task.taskId);
});
</script>
Hope this makes sense and helps ...
Let me know if you need anything else.
Have fun!
回答2:
Node is asynchronous. Use callbacks or promises to make sure that the result page is shown only when the calculations has been completed.
来源:https://stackoverflow.com/questions/35720587/express-js-res-render-and-res-redirect