C++二维数组名的再探索

#include <iostream>

int main()
{
    
    int d2a[3][4] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 };

    //输出 0,1,2,3,4,5,6,7,8,9,10,11
    for (size_t i = 0; i < 3; i++)
    {
        for (size_t j = 0; j < 4; j++)
        {
            std::cout << d2a[i][j] << ",";
        }
    }

    //输出 0077FD04,0077FD04,0077FD14,0077FD24
    //可见二维数组名是数据首地址，d2a[0],d2a[1],d2a[2]分别是第一行，第二行，第三行的首地址
    std::cout << d2a << "," << d2a[0] << "," << d2a[1] << "," << d2a[2] << std::endl;

    //最直观的顺序输出所有元素的方式
    //输出 0,1,2,3,4,5,6,7,8,9,10,11
    int* pa = (int*)d2a;
    for (size_t i = 0; i < 12; i++)
    {
        std::cout << *(pa + i) << ",";
    }
    
    //最难理解的二维数组名当指针的输出方式
    //输出 0,1,2,3,4,5,6,7,8,9,10,11
    for (size_t i = 0; i < 12; i++)
    {
        std::cout << *(*d2a + i) << ",";
        
        //错误方式，虽然二维数组指向数组首地址，但相当于行指针，d2a+0 = d2a[0], d2a+1 = d2a[1],d2a+2=d2a[2]
        //std::cout << *(d2a + i) << ",";

    }


    //理解了二维数组名的实质后，下面的就容易理解了
    char str[] = "ab";
    char(*px)[3] = &str;

    (*px)[0] = 'a';
    (*px)[1] = 'b';
    (*px)[2] = 'c';
}

 

来源：https://www.cnblogs.com/timeObjserver/p/12002918.html