Remove “/” from api call when optional parameter is null

问题

We are using RESTful Web Services (Jersey) for API calls on java. While API needs optional parameter, we are doing as:

api-interface/user/userid/9000/companyid/90909/{optionalparameter*}

and we have to call this api when there is no optional parameter as:

api-interface/user/userid/9000/companyid/90909/

What needed is:

Case:1 If optional parameter exists

api-interface/user/userid/9000/companyid/90909/name/john/address/MA/age/34

Case:2 If Optional parameter doesn't exists.

api-interface/user/userid/9000/companyid/90909

My present implementation is:

@GET
@Path("user/companyid/{companyid}/userid/{userid}/{optionalparameter:.*}")
@Produces(MediaType.APPLICATION_JSON)
    public Response getUserList(@PathParam("companyid") String companyId, @PathParam("userid") String userId,
            @PathParam("optionalparameter") String syncDate) throws BadRequestException, InternalServerException {
    //parsing the param.
  }

In above code, I need to add trailing "/" but I am looking the way to remove this trailing "/" if anybody doesn't wants to pass those param.

I followed this link but it didn't worked while the preceding parameter's length is more then 1.

Please, Suggest me the best way.

回答1:

Looking at your reference, have you tried this:

@Path("userid/{userid}/companyid/{companyid}{optparam:(/[^/]+?)*}")
public Response getLocation(
        @PathParam("userid") int userid,
        @PathParam("companyid") int companyid,
        @PathParam("optparam") String optparam) {
    String[] params = parseParams(optparam);
    ...
}

private String[] parseParams(String params) {
    if (params.startsWith("/")) {
        params = path.substring(1);
    }
    return params.split("/");
}

That should work, giving you all the parameters in a single array.

EDIT: I have updated the search string and verified it on a local install.

来源：https://stackoverflow.com/questions/26377710/remove-from-api-call-when-optional-parameter-is-null

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jersey