问题
I am trying to get accustomed to rxjava and I am trying to call the below QuoteReader in an Observable. I am not sure how to handle the exception thrown,
public class QuoteReader {
public Map<String, Object> getQuote() throws IOException{
OkHttpClient okHttpClient = new OkHttpClient();
Request request = new Request.Builder().url("http://quotes.rest/qod.json").build();
Gson gson = new Gson();
Map<String, Object> responseMap = null;
try(Response response = okHttpClient.newCall(request).execute()) {
responseMap = gson.fromJson(response.body().string(), Map.class);
System.out.println("response map : "+responseMap);
} catch(IOException ioe) {
ioe.printStackTrace();
throw ioe;
} finally {
okHttpClient = null;
request = null;
}
return responseMap;
}
}
The following is the rx code I am trying to write,
rx.Observable.just(new QuoteReader().getQuote()) //compile time error saying unhandled exception
.subscribe(System.out::println);
How should I update the code to handle the exception. Thanks!
回答1:
Use fromCallable that allows your method to throw (plus, it gets evaluated lazily and not before you even get into the Observable world):
rx.Observable.fromCallable(() -> new QuoteReader().getQuote())
.subscribe(System.out::println, Throwable::printStackTrace);
回答2:
There is another factory method for an Observable, which is called create. This gives you an Observer as input of a lambda expression. Observer is a kind of callback object with three methods: onNext(T t), onError(Throwable e) and onCompleted. I read you're new to RxJava, so here is a little extra as a sidenote: the Rx contract specifies that an Observer can receive zero or more onNext calls, followed by maybe either an onError or onCompleted call. In regular expression for this looks like: onNext* (onError|onCompleted)?.
Now that you know this, you can implement your operation using Observable.create:
Observable.create(observer -> {
try {
observer.onNext(new QuoteReader.getQuote());
observer.onCompleted();
}
catch (Throwable e) {
observer.onError(e);
}
}
Notice that this code doesn't do anything until you subscribe to this Observable as you already did in your question!
回答3:
Observable pipeline does not allow you throw Exceptions. You must use runtimeExceptions. So changing your code it should looks like.
try(Response response = okHttpClient.newCall(request).execute()) {
responseMap = gson.fromJson(response.body().string(), Map.class);
System.out.println("response map : "+responseMap);
} catch(IOException ioe) {
ioe.printStackTrace();
new RuntimeException(ioe);
You can see a practical example here https://github.com/politrons/reactive/blob/master/src/test/java/rx/observables/errors/ObservableExceptions.java
来源:https://stackoverflow.com/questions/37906875/exception-handling-in-rxjava