Behavior of 'subsref' for arrays of objects

问题

Imagine a simple array of structures, say:

A = struct('x', {1 2 3}, 'y', {'a' 'b' 'c'});

Asking for a given property for all this array's elements will give something like:

>> A.x
ans =
     1
ans =
     2
ans =
     3

Now, if I explicitly call the subsref function directly on this array, it only retrieves the first element's property:

>> builtin('subsref', A, substruct('.', 'x'))
ans = 
     1

Why? And is there a possibility to call explicitly another built-in method that will retrieve the property for all the array's elements?

回答1:

The subsref method can return it but not as a comma separated list the way you get it in the interpreter. It returns them as separate output arguments that means:

>> [a,b,c]=builtin('subsref', A(:), substruct('.', 'x'))
a =
     1
b =
     2
c =
     3

you can capture the output in a cell array if you like

>> [x{1:numel(A)}]=builtin('subsref', A(:), substruct('.', 'x'))
x = 
    [1]    [2]    [3]

来源：https://stackoverflow.com/questions/30236807/behavior-of-subsref-for-arrays-of-objects