问题
When developing stuff I need to output the state of some instance in order to inspect it.
While using CakePHP I always had a debug() function which does some kind of var_dump inside a <pre> html element, so the content is readable.
Is something similar in Symfony 2.x too?
回答1:
exit(\Doctrine\Common\Util\Debug::dump($someVar));
回答2:
use
\Doctrine\Common\Util\Debug::dump($user);
回答3:
As of today, one of the best ways to debug in Symfony that I know of is the Ladybug Bundle. Its output is similar to xdebug's, but it has some nice features, like a collapsible tree structure for arays or automatically linking to documentation pages (supporting standard PHP, Doctrine and Symfony).
You can find some great examples of its use on the README.
回答4:
Now there is a new function in Symfony - dump(), have a look at http://symfony.com/blog/new-in-symfony-2-6-vardumper-component
来源：https://stackoverflow.com/questions/15604565/pretty-dump-variable-object-in-symfony-2