How to convert string into bits and then into int array - java

问题

How to convert string into bits(not bytes) or array of bits in Java(i will do some operations later) and how to convert into array of ints(every 32 bits turn into the int and then put it into the array? I have never done this kind of conversion in Java.

String->array of bits->(some operations I'll handle them)->array of ints

回答1:

ByteBuffer bytes = ByteBuffer.wrap(string.getBytes(charset));
  // you must specify a charset
IntBuffer ints = bytes.asIntBuffer();
int numInts = ints.remaining();
int[] result = new int[numInts];
ints.get(result);

回答2:

THIS IS THE ANSWER

String s = "foo";
      byte[] bytes = s.getBytes();
      StringBuilder binary = new StringBuilder();
      for (byte b : bytes)
      {
         int val = b;
         for (int i = 0; i < 8; i++)
         {
            binary.append((val & 128) == 0 ? 0 : 1);
            val <<= 1;
         }
      //   binary.append(' ');
      }
      System.out.println("'" + s + "' to binary: " + binary);

回答3:

You are looking for this:

string.getBytes();

Not list, it's an array but you can use it later on, even to convert it to integers.

回答4:

Well, maybe you can skip the String to bits conversion and convert directly to an array of ints (if what you want is the UNICODE value of each character), using s.toCharArray() where s is a String variable.

回答5:

This will convert "abc" to byte and then the code will print "abc" in respective ASCII code (ie. 97 98 99).

byte a[]=new byte[160];
String s="abc";
a=s.getBytes();
for(int i=0;i<s.length();i++)
{
    System.out.print(a[i]+" ");
}

回答6:

May be so (I have no compiler in my current computer and don't test if it work, but it can help you a bit):

String st="this is a string";
byte[] bytes=st.getBytes();
List<Integer> ints=new ArrayList<Integer>();
ints.addAll(bytes);

If compiler fails in

ints.addAll(bytes);

you can replace it with

for (int i=0;i<bytes.length();i++){
   ints.add(bytes[i]);
}

and if you want to get exactly array:

ints.toArray();

回答7:

Note that string is a sequence of chars, and in Java each char data type is a single 16-bit Unicode character. It has a minimum value of '\u0000' (or 0) and a maximum value of '\uffff' (or 65,535 inclusive). In order to get char integer value do this:

    String str="test";
    String tmp="";

    int result[]=new int[str.length()/2+str.length()%2];
    int count=0;

    for(char c:str.toCharArray()) {
         tmp+=Integer.toBinaryString((int)c);
         if(tmp.length()==14) {
            result[count++]=Integer.valueOf(tmp,2);
            //System.out.println(tmp+":"+result[count-1]);
            tmp="";
         }
    }

    for(int i:result) {
        System.out.print(i+" ");
    }

来源：https://stackoverflow.com/questions/11367611/how-to-convert-string-into-bits-and-then-into-int-array-java

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java

string

int

bit

bits