问题
This is what I'm doing
a = "%span.rockets#diamonds.ribbons.forever"
a = a.match(/(^\%\w+)([\.|\#]\w+)+/)
puts a.inspect
This is what I get
#<MatchData "%span.rockets#diamonds.ribbons.forever" 1:"%span" 2:".forever">
This is what I want
#<MatchData "%span.rockets#diamonds.ribbons.forever" 1:"%span" 2:".rockets" 3:".#diamonds" 4:".ribbons" 5:".forever">
help? I tried and failed :(
回答1:
Generally, you can't get an arbitrary number of capturing groups, but if you use scan you can get a match for every token you want to capture:
a = "%span.rockets#diamonds.ribbons.forever"
a = a.scan(/^%\w+|\G[.|#]\w+/)
puts a.inspect
["%span", ".rockets", "#diamonds", ".ribbons", ".forever"]
This isn't too different from your regex, but I removed repetition on the last token. \G isn't too well known - it tells the engine to match where the previous match ended, so it doesn't break when you have extra characters between matches (%span :P .rockets).
Generally, if you had multiple matches of your original regex this method may add some work, because you don't have the groups separated to matches, but since match returns a single result it should work fine.
Working example: http://ideone.com/nnmki
回答2:
That's just how capturing groups work. If you want to save all of those substrings, put the quantifier inside the capturing group:
a = a.match(/(^%\w+)((?:[.#]\w+)+)/)
Then your second capture will be:
2:".rockets#diamonds.ribbons.forever"
...and you can break it down the rest of the way yourself.
来源：https://stackoverflow.com/questions/3648657/regex-saving-repeating-captured-group