问题
So we know that the standard doesn't force pointer sizes to be equal. (here and here) (and not talking about function pointers)
I was wondering how in reality that can be an issue. We know that void * can hold anything, so if the pointer sizes are different, that would be the biggest size. Given that, assigning a void ** to a char ** means trouble.
My question is how dangerous would it be to assume void * and char * have the same size? Is there actually an architecture where this is not true?
Also, 16-bit dos is not what I want to hear! ;)
回答1:
void * and char * are guaranteed to have the same size.
void ** is not guaranteed to have the same size as char ** (but very likey on your implementation they will).
(C99, 6.2.5p27) "A pointer to void shall have the same representation and alignment requirements as a pointer to a character type [...] Pointers to other types need not have the same representation or alignment requirements."
回答2:
Assigning pointers of different object types to each other is allowed as long as no alignment requirements are violated: The assignment will involve an (implicit) type conversion, so it is as (un)problematic as assigning a float to an int - it works in most cases but is allowed to blow up when a meaningful conversion is impossible.
char * and void * have compatible alignment requirements per spec, so assigning a char ** to a void ** variable (and vice versa) is never problematic. They even have compatible representation, which means in principle, accessing a char * through an expression of type void * - eg by dereferening a void ** which actually points to a char * - will work as expected in most cases. Of course, the converse (accessing a void * by dereferencing a char **) holds true as well.
For example, the p conversion specifier for printf() expects a void * and passing in an arbitrary pointer type is undefined behaviour. However, in case of char *, it should work even on exotic architectures (eg with different pointer representations) as long as the implementation conforms to the C standard.
Where problems may arise is aliasing analysis: Due to the effective typing rules, a void ** and a char ** can't alias, and if the programmer breaks that promise, strange things may happen. One should realize that because of effective typing (aka strict aliasing), C is actually strongly typed - the type system is just very unsound (ie doesn't protect you from violating its invariants)...
来源：https://stackoverflow.com/questions/11275713/how-dangerous-is-conversion-from-void-to-char