问题
Forgive me if this might be a bit of a noobie question, but this should work shouldn't it?
var elems = [1,2,3,4,5]
for (var i = 0; i <elems.length; i++) {
return (function(e){
console.log(e)
})(i);
}
Meaning, it should spit out
>>node file.js
1
2
3
4
5
For some reason this isn't doing this. Rather when it is run in terminal, it spits out
>>node file.js
1
What am I missing? Could you please elaborate.
回答1:
Because you are returning the value returned by the IIFE immediately, in this statement
return (function(e){
console.log(e)
})(i);
since the IIFE just prints 0 and doesn't return anything explicitly, JavaScript will return undefined by default and exit immediately. To fix this, just drop the return keyword,
(function(e){
console.log(e)
})(i);
PS: Have you ever wondered, why the return statement in the above code works? To think about it, it is not inside a function. Then technically its an error, right? ;-) I explained this in detail, in this question.
回答2:
When you call the return, it will immediately break out of the loop. If you want to return all the values, you will have to put them in a container and return the container.
来源:https://stackoverflow.com/questions/28953795/for-loop-saving-state-with-closure