问题
I'm making a TreeMap<String, String>
and want to order it in a descending fashion. I created the following comparator:
Comparator<String> descender = new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
return o2.compareTo(o1);
}
};
I construct the TreeMap like so:
myMap = new TreeMap<String, String>(descender);
However, I'm getting the following error:
The method compare(String, String) of type new Comparator<String>(){} must override a superclass method
I've never fully groked generics, what am I doing wrong?
回答1:
Your Eclipse project is apparently set to Java 1.5. The @Override
annotation is then indeed not supported on interface methods. Either remove that annotation or fix your project's compliance level to Java 1.6.
回答2:
You don't need to write a custom Comparator
if you just want to reverse the natural (ascending) ordering.
To get a descending ordering just use:
myMap = new TreeMap<String, String>(java.util.Collections.reverseOrder());
回答3:
Ah, I found the problem. When instantiating a new anonymous instance of a Comparable, I'm not overriding the interfaces methods... I'm implementing them. The @Override directive was the problem. The compare() method wasn't overriding an existing method, it was implementing part of the interface. I copied that code from another place and it shouldn't have had the @Override.
来源:https://stackoverflow.com/questions/7223512/comparatorstring-must-override-super-class-method