What is the neatest way to split out a Path Name into its components in Lua

ぐ巨炮叔叔 提交于 2019-12-06 17:12:41

问题


I have a standard Windows Filename with Path. I need to split out the filename, extension and path from the string.

I am currently simply reading the string backwards from the end looking for . to cut off the extension, and the first \ to get the path.

I am sure I should be able to do this using a Lua pattern, but I keep failing when it comes to working from the right of the string.

eg. c:\temp\test\myfile.txt should return

  • c:\temp\test\
  • myfile.txt
  • txt

Thank you in advance apologies if this is a duplicate, but I could find lots of examples for other languages, but not for Lua.


回答1:


> return string.match([[c:\temp\test\myfile.txt]], "(.-)([^\\]-([^%.]+))$")
c:\temp\test\   myfile.txt  txt

This seems to do exactly what you want.




回答2:


Here is an improved version that works for Windows and Unix paths and also handles files without dots (or files with multiple dots):

= string.match([[/mnt/tmp/myfile.txt]], "(.-)([^\\/]-%.?([^%.\\/]*))$")
"/mnt/tmp/" "myfile.txt"    "txt"

= string.match([[/mnt/tmp/myfile.txt.1]], "(.-)([^\\/]-%.?([^%.\\/]*))$")
"/mnt/tmp/" "myfile.txt.1"  "1"

= string.match([[c:\temp\test\myfile.txt]], "(.-)([^\\/]-%.?([^%.\\/]*))$")
"c:\\temp\\test\\"  "myfile.txt"    "txt"

= string.match([[/test.i/directory.here/filename]], "(.-)([^\\/]-%.?([^%.\\/]*))$")
"/test.i/directory.here/"   "filename"  "filename"



回答3:


Split string in Lua?

There is a few string to table functions there, split "\" as \ cant be in a folder name anyway so you'll end up with a table with index one being the drive and the last index being the file.



来源:https://stackoverflow.com/questions/5243179/what-is-the-neatest-way-to-split-out-a-path-name-into-its-components-in-lua

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