RxJS distinctUntilChanged - object comparsion

问题

I have stream of objects and I need to compare if current object is not same as previous and in this case emit new value. I found distinctUntilChanged operator should do exactly what I want, but for some reason, it never emit value except first one. If i remove distinctUntilChanged values are emited normally.

My code:

export class SettingsPage {
    static get parameters() {
        return [[NavController], [UserProvider]];
    }

    constructor(nav, user) {
        this.nav = nav;
        this._user = user;

        this.typeChangeStream = new Subject();
        this.notifications = {};
    }

    ngOnInit() {

        this.typeChangeStream
            .map(x => {console.log('value on way to distinct', x); return x;})
            .distinctUntilChanged(x => JSON.stringify(x))
            .subscribe(settings => {
                console.log('typeChangeStream', settings);
                this._user.setNotificationSettings(settings);
            });
    }

    toggleType() {
        this.typeChangeStream.next({
            "sound": true,
            "vibrate": false,
            "badge": false,
            "types": {
                "newDeals": true,
                "nearDeals": true,
                "tematicDeals": false,
                "infoWarnings": false,
                "expireDeals": true
            }
        });
    }

    emitDifferent() {
        this.typeChangeStream.next({
            "sound": false,
            "vibrate": false,
            "badge": false,
            "types": {
                "newDeals": false,
                "nearDeals": false,
                "tematicDeals": false,
                "infoWarnings": false,
                "expireDeals": false
            }
        });
    }
}

回答1:

I had the same problem, and fixed it with using JSON.stringify to compare the objects:

.distinctUntilChanged((a, b) => JSON.stringify(a) === JSON.stringify(b))

Dirty but working code.

回答2:

I finally figure out where problem is. Problem was in version of RxJS, in V4 and earlier is different parameters order than V5.

RxJS 4:

distinctUntilChanged = function (keyFn, comparer)

RxJS 5:

distinctUntilChanged = function (comparer, keyFn)

In every docs today, you can find V4 parameters order, beware of that!

回答3:

When you have lodash in your application anyway, you can simply utilize lodash's isEqual() function, which does a deep comparison and perfectly matches the signature of distinctUntilChanged():

.distinctUntilChanged(isEqual),

Or if you have _ available (which is not recommended anymore these days):

.distinctUntilChanged(_.isEqual),

回答4:

Mehdi's solution although fast but wouldn't work if the order is not maintained. Using one of deep-equal or fast-deep-equal libraries:

.distinctUntilChanged((a, b) => deepEqual(a, b))

回答5:

If you change the value mutably, none of the other answers work. If you need to work with mutable data structures, you can use distinctUntilChangedImmutable, which deep copies the previous value and if no comparison function is passed in, will assert that the previous and the current values deep equals each other (not === assertion).

回答6:

From RxJS v6+ there is distinctUntilKeyChanged

https://www.learnrxjs.io/operators/filtering/distinctuntilkeychanged.html

const source$ = from([
  { name: 'Brian' },
  { name: 'Joe' },
  { name: 'Joe' },
  { name: 'Sue' }
]);

source$
  // custom compare based on name property
  .pipe(distinctUntilKeyChanged('name'))
  // output: { name: 'Brian }, { name: 'Joe' }, { name: 'Sue' }
  .subscribe(console.log);

来源：https://stackoverflow.com/questions/37172395/rxjs-distinctuntilchanged-object-comparsion