How to return the next letter in the alphabet of given letter wrapped around in Haskell [closed]

对着背影说爱祢 提交于 2019-12-06 16:06:16

Two ways come to mind

import Data.Char
returnNext c = chr (((1 + ord c - ord 'A') `mod` 26) + ord 'A')

Which is kind of ugly to say the least.

And:

returnNext 'Z' = 'A'
returnNext c = chr (ord c + 1)

Both behave differently when not given a letter of the alphabet, but since you didn't specify what should happen in this case I'll assume it's OK.

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