class Solution {
public int lengthLongestPath(String input) {
String [] arr=input.split("\n");
int [] lens= new int[arr.length];
int max=0;
for(String s:arr){
int lastBackT= s.lastIndexOf("\t");
int level = lastBackT+1;
int parentLen = level==0? 0: lens[level-1]+1;
int nameLen = s.length()-lastBackT-1;
lens[level] = parentLen+nameLen;
if(s.contains("."))
{
max = Math.max(max,lens[level]);
}
}
return max;
}
}
The first thought is DFS, however, we're able to deal it with array