I saw there are other questions about the dot "." I followed but it didn't work for my code.... it's a part of code, the implementation is not focused to this symbol. but output should be included this dot. when I give input of two lists '(1 2 3) '(4 5) my expected output => (1 . 4) (2 . 5)
I managed to get (1 4) (2 5) just need to add "." in the middle.
Part of mycode
(cons (list (car lst1) (car lst2))
....
for the "." symbol , if I try
**trial-1**
(cons '(list (car lst1) (car lst2)) ...)
then the output : ((list (car lst1) (car lst2))
**trail-2**
(cons (list (car lst1) '. (car lst2)) ...)
then.. it says : illegal use of `.'
what are the rules to use the dot? any documents I can look at? btw, I am using Racket(R5RS).
The dot symbol is displayed when you build a cons-pair or a list which is not proper (meaning: it doesn't end with the empty list). For example:
(cons 1 2)
=> (1 . 2) ; a cons-pair
(cons 1 (cons 2 (cons 3 4)))
=> '(1 2 3 . 4) ; an improper list
For instance, to display an output such as the one shown in the question try this:
(define lst1 '(1 2 3))
(define lst2 '(4 5))
(list (cons (car lst1) (car lst2))
(cons (cadr lst1) (cadr lst2)))
=> '((1 . 4) (2 . 5))
Although . can be a part of a symbol, . is not in itself a valid symbol. . is used in list structure as a divider between the car and the cdr. eg. (a . (b . (c . ()))) ; ==> (a b c).
Practical application is the historic use as a rest argument in the prototype of a procedure and you can use it as template an transformation of macros. Also, read can read it in and you can use it as data like (define lst '((a) . (b))).
So to recap:
(a . b) is a pair of a and b, while (a.b) is the same as (a.b . ()) thus a pair of the symbol a.b and the empty list.
As for how to create a pair you use cons. (cons 'a 'b) => (a . b) while (list a b) => (cons 'a (cons b '())). Now you can make a pair with two lists as arguments, (cons '(1 4) '(2 5)) but if you print it you know that (a . (b)) is the same as (a b) thus (cons '(1 4) '(2 5)) will display as ((1 4) 2 5) since it will prefer not to display the dot. If it would prefer to show dots it would have displayed it as ((1 . (4 . ())) . ((2 . (5 . ())))) instead since thats how many pairs there are in that data structure.
If you have managed to get the output ((1 4) (2 5)) and really wanted ((1 . 4) (2 . 5)) you need to replace a list with cons.
It's called a dotted pair and is produced when you cons an item with a non-list, such as:
> (cons 1 2)
(1 . 2)
See: http://download.plt-scheme.org/doc/html/guide/Pairs__Lists__and_Scheme_Syntax.html
From R7RS:
The most general notation (external representation) for Scheme pairs is the “dotted” notation (c1 . c2) where c1 is the value of the car field and c2 is the value of the cdr field. For example (4 . 5) is a pair whose car is 4 and whose cdr is 5. Note that (4 . 5) is the external repre- sentation of a pair, not an expression that evaluates to a pair.
. is not a symbol.
来源：https://stackoverflow.com/questions/23620331/about-the-dot-in-scheme