findAll() from Sequelize doesn't get

问题

I'm using Sequelize with MySQL.

When I run this code:

usuarioService.getAll = function () {
    Usuario.findAll().then(function (users) {
        //return users;
        console.dir(users);
    });
}

Instead of get the user, I get:

http://i.stack.imgur.com/uLhmN.png

Help me, please! I'm going crazy!

Thanks

回答1:

Sequelize is returning an array of instance objects in users. An instance object has a number of convenience methods attached to it that allow you to act on it.

If you want to get just the data with your fields as keys, use get({plain: true}). For example, for the first object in the array users[0].get({plain: true}). If you want to keep using the instances, you can just use get with the name of your field. For example, users[0].get('nombre').

You should be also able to access the properties directly on the object, even if they're not being logged, such as users[0].nombre.

Edit

This is not related to the original question, but your comment on another answer. Make sure you are doing things asynchronously. The code should be:

usuarioService.getAll = function (cb) {
    Usuario.findAll().then(function (users) {
        return cb(null, users);
    }).catch(function(err) {
        return cb(err);
    });
}

Then when calling this method you would do something like:

router.get('your_path', function(req, res, next) {
    serv.getAll(function(err, users) {
        if (err) {
            // your err handling code
        }
        // users is now a valid js array
        // could send it in res.json(users)
    });
});

or

Since Sequelize uses promises, doing this using promises would be the best way.

usuarioService.getAll = function () {
    return Usuario.findAll({ raw: true });
}

Then when calling this method you would do something like:

router.get('your_path', function(req, res, next) {
    serv.getAll().then(function(users) {
        res.render('usuarios/index',{
            users: users
        })
    }).catch(function(err) {
        // your error handling code here
    });
});

回答2:

You are returning a user.

The first bit you see is the SQL query that Sequelize is executing for you.

The bit that says

dataValues: 
   { usuario_id: 1,
    ... 
   }

is your user. findAll() should give you an array with all of your users.

If you just want the dataValues returned you can just pass in raw: true.

usuarioService.getAll = function () {
    Usuario.findAll({ raw: true }).then(function (users) {
        //return users;
        console.dir(users);
    });
}

来源：https://stackoverflow.com/questions/36214221/findall-from-sequelize-doesnt-get