Write byte at address (hexedit/modify binary from the command line)

问题

Is there any straightforward way to modify a binary from the commandline? Let's say I know that my binary contains 1234abcd and i want to change it to 12FFabcd or FFFFabcd or maybe even FF34FFabc0 (you get the idea) :-)

How might I achieve that without using any special purpose tools like http://stahlworks.com/dev/swiss-file-knife.html or similar.

It would be great to do it just from the commandline with only standard linux tools.

Or maybe even better instead for searching for the hex string i want to replace directly writing FF at Offset 0x10000, 12 at Offset 0x100001 and so on.

It should be scriptable and run directly from the commandline. I am looking for something like "binary-which-is-included-in-the-distro --write AB --at-offset 100000 --file thebinary.bin". I am quite sure that it is possible with "dd", but I wasn't able to wrap my head around the man page.

Any idea?

Thanks in advance!

回答1:

printf '\x31\xc0\xc3' | dd of=test_blob bs=1 seek=100 count=3 conv=notrunc

dd arguments:

of | file to patch
bs | 1 byte at a time please
seek | go to position 100 (decimal)
conv=notrunc | don't truncate the output after the edit (which dd does by default)

One Josh looking out for another ;)

回答2:

The printf+dd based solutions do not seem to work for writing out zeros. Here is a generic solution in python3 (included in all modern distros) which should work for all byte values...

#!/usr/bin/env python3
#file: set-byte

import sys

fileName = sys.argv[1]
offset = int(sys.argv[2], 0)
byte = int(sys.argv[3], 0)

with open(fileName, "r+b") as fh:
    fh.seek(offset)
    fh.write(bytes([byte]))

Usage...

set-byte eeprom_bad.bin 0x7D00 0
set-byte eeprom_bad.bin 1000 0xff

Note: This code can handle input numbers both in hex (prefixed by 0x) and dec (no prefix).

回答3:

Here's a Bash function replaceByte, which takes the following parameters:

the name of the file,
an offset of the byte in the file to rewrite, and
the new value of the byte (a number).

#!/bin/bash

# param 1: file
# param 2: offset
# param 3: value
function replaceByte() {
    printf "$(printf '\\x%02X' $3)" | dd of="$1" bs=1 seek=$2 count=1 conv=notrunc &> /dev/null
}

# Usage:
# replaceByte 'thefile' $offset 95

回答4:

xxd tool, which comes with vim (and thus is quite likely to be available) allows to hex dump a binary file and construct a new binary file from a modified hex dump.

回答5:

Writing the same byte at two different positions in the same file with a one liner.

printf '\x00'| tee >(dd of=filename bs=1 count=1 seek=692 conv=notrunc status=none) \
    >(dd of=filename bs=1 count=1 seek=624 conv=notrunc status=none)

status=none very useful when you don't want any statistics out of dd.

回答6:

If you don't need it to be scriptable, you could try the "hexedit" utility. It is available in many Linux distributions (if not installed by default, it can usually be found in the distro's package repository).

If your distro doesn't have it, you can build and install it from source.

回答7:

Some alternatives:

HexAlter (open source compiled tool)
ucon64 --nbak --poke=OFF:V FILE (meant for ROM dumps, should work with any binary file, but no inplace editing)
printf '\x31' | dd of=FILE bs=1 seek=OFFSET count=1 conv=notrunc (wrapped in a shellscript like this that also allows reading)

回答8:

Regarding Josh answer: In case you want to do it for a specific address

hexdump -C {file location}

with some hex value you might have tried to add 0x but it would fail :

dd: warning: ‘0x’ is a zero multiplier; use ‘00x’ if that is intended

You can achieve this by encapsulating it with $(()) that the terminal will translate as an int value :

mybinary={file location}
printf '\x31\xc0\xc3' | dd of=$mybinary bs=1 seek=$((0x100)) count=3 conv=notrunc

来源：https://stackoverflow.com/questions/4783657/write-byte-at-address-hexedit-modify-binary-from-the-command-line

标签

shell

scripting

hex

patch

edit