问题
I have 2 tables: projects, project_types.
The relations are as follow:
Project => belong to => ProjectType
ProjectType => hasMany => Project
The columns are as follow
Project => id, project_type_id, name, description
ProjectType => id, name
How can I create a virtual field called projectTypeName with the name from projectType based on project_type_id and for those that project_type_id = 0, it will be ""
I have this
public $virtualFields = array(
'projectTypeName' => "IF(Project.project_type_id = 9, 'sales', '')"
);
it correctly shows as "sales" but I don't want to specify it one by one.
Thank you
回答1:
This works for me
public $virtualFields = array(
'projectTypeName' => 'SELECT name FROM project_types where id = Project.project_type_id'
);
来源:https://stackoverflow.com/questions/20413830/cakephp-how-to-create-virtual-field-based-off-another-table