How To Use XmlDsigC14NTransform Class in C#

亡梦爱人 提交于 2019-12-06 03:26:33

问题


I am trying to canonicalize an xml node by using System.Security.Cryptography.Xml.XMLDsigC14nTransform class of c# .net Framework 2.0.

The instance expects three different input types, NodeList, Stream and XMLDocument. I try the transform with all of these input types but I get different results. What I really want to do is to canonicalize a single node, but as you can see in the output file, the output does not contain any of the inner xml.

Any suggestions about the proper way to canonicalize an XML Node are very appreciated. Best,

string path = @"D:\Test\xml imza\sign.xml";
XmlDocument xDoc = new XmlDocument();
xDoc.PreserveWhitespace = true;
using (FileStream fs = new FileStream(path, FileMode.Open))
{
    xDoc.Load(fs);
}

// canon node list
XmlNodeList nodeList = xDoc.SelectNodes("//Child1");

XmlDsigC14NTransform transform = new XmlDsigC14NTransform();
transform.LoadInput(nodeList);
MemoryStream ms = (MemoryStream)transform.GetOutput(typeof(Stream));

File.WriteAllBytes(@"D:\Test\xml imza\child1.xml", ms.ToArray());

// canon XMLDocument
transform = new XmlDsigC14NTransform();
transform.LoadInput(xDoc);
ms = (MemoryStream)transform.GetOutput(typeof(Stream));

File.WriteAllBytes(@"D:\Test\xml imza\doc.xml", ms.ToArray());

// Document to Stream
ms = new MemoryStream();
XmlWriter xw = XmlWriter.Create(ms);
xDoc.WriteTo(xw);
xw.Flush();
ms.Position = 0;

transform = new XmlDsigC14NTransform();
transform.LoadInput(ms);
ms = (MemoryStream)transform.GetOutput(typeof(Stream));

File.WriteAllBytes(@"D:\Test\xml imza\ms.xml", ms.ToArray());

// node to stream
ms = new MemoryStream();
xw = XmlWriter.Create(ms);
nodeList[0].WriteTo(xw);
xw.Flush();
ms.Position = 0;

transform = new XmlDsigC14NTransform();
transform.LoadInput(ms);
ms = (MemoryStream)transform.GetOutput(typeof(Stream));

File.WriteAllBytes(@"D:\Test\xml imza\ms2.xml", ms.ToArray());

sign.xml

<?xml version="1.0" encoding="utf-8" ?>
<Root Attr="root" xmlns:test="http://www.test.com/xades#">
  <Child1 Cttribute="c3" Attribute1="c1" Bttribute="c2">
    <child11 Attribute11="c11">Element11</child11>
  </Child1>
  <Child2 Attribute2="c2">
    <child21 Attribute21="c21">Element21</child21>
    <child22 Attribute22="c22">Element22</child22>
  </Child2>
  <Child3 Attribute3="c3">
    <child31 Attribute32="c31">
      <child311 Attribute311="c311">Element311</child311>
    </child31>
  </Child3>  
</Root>

Child1.xml

<Child1 xmlns:test="http://www.test.com/xades#"></Child1>

doc.xml

<Root xmlns:test="http://www.test.com/xades#" Attr="root">&#xD;
  <Child1 Attribute1="c1" Bttribute="c2" Cttribute="c3">&#xD;
    <child11 Attribute11="c11">Element11</child11>&#xD;
  </Child1>&#xD;
  <Child2 Attribute2="c2">&#xD;
    <child21 Attribute21="c21">Element21</child21>&#xD;
    <child22 Attribute22="c22">Element22</child22>&#xD;
  </Child2>&#xD;
  <Child3 Attribute3="c3">&#xD;
    <child31 Attribute32="c31">&#xD;
      <child311 Attribute311="c311">Element311</child311>&#xD;
    </child31>&#xD;
  </Child3>  &#xD;
</Root>

ms.xml

<Root xmlns:test="http://www.test.com/xades#" Attr="root">
  <Child1 Attribute1="c1" Bttribute="c2" Cttribute="c3">
    <child11 Attribute11="c11">Element11</child11>
  </Child1>
  <Child2 Attribute2="c2">
    <child21 Attribute21="c21">Element21</child21>
    <child22 Attribute22="c22">Element22</child22>
  </Child2>
  <Child3 Attribute3="c3">
    <child31 Attribute32="c31">
      <child311 Attribute311="c311">Element311</child311>
    </child31>
  </Child3>  
</Root>

ms2.xml

<Child1 Attribute1="c1" Bttribute="c2" Cttribute="c3">
    <child11 Attribute11="c11">Element11</child11>
  </Child1>

回答1:


I think, your answer is in your question, "What I really want to do is to canonicalize a single node, but as you can see in the output file, the output does not contain any of the inner xml."

If I understand you, then really you don't want to canonicalise a single node, or you'd be happy that it doesn't contain the inner XML. You want to canonicalise a single subtree.

XPath returns nodes, not subtrees. Some operations on the nodes returned by an XPath expression will then include their child and attribute nodes by default, but canonicalisation deliberately isn't one of these, as potentially some of those very child nodes could be mutable in ways that you are not signing. In signing, you are only signing precisely those nodes that you say you are signing.

Changing the line in your code from:

XmlNodeList nodeList = xDoc.SelectNodes("//Child1");

to:

XmlNodeList nodeList =
    xDoc.SelectNodes("//Child1/descendant-or-self::node()|//Child1//@*");

Means I get the following in child1.xml:

<Child1 xmlns:test="http://www.test.com/xades#" Attribute1="c1" Bttribute="c2" Cttribute="c3">&#xD;
    <child11 Attribute11="c11">Element11</child11>&#xD;
  </Child1>

Am I correct in thinking that this is what you want?

Incidentally, more precision along the lines of:

XmlNodeList nodeList =
    xDoc.SelectNodes("//Child1[1]/descendant-or-self::node()|//Child1[1]//@*");

May be useful, as then the xpath evaluation can stop when it gets to the first </Child1>, with a performance gain that could be significant if your real data is large.




回答2:


I found probably the solution at MSDN If I got the problem correctly.

Does this solve the problem?:

string path = @"sign.xml";
var xDoc = new XmlDocument();
xDoc.PreserveWhitespace = true;
using (var fs = new FileStream(path, FileMode.Open))
{
    xDoc.Load(fs);
}

// canon node list
XmlNodeList nodeList = xDoc.SelectNodes("//Child1");

var transform = new XmlDsigC14NTransform(true)
                    {
                        Algorithm = SignedXml.XmlDsigExcC14NTransformUrl
                    };

var validInTypes = transform.InputTypes;
var inputType = nodeList.GetType();
if (!validInTypes.Any(t => t.IsAssignableFrom(inputType)))
{
    throw new ArgumentException("Invalid Input");
}

transform.LoadInput(xDoc);
var innerTransform = new XmlDsigC14NTransform();

innerTransform.LoadInnerXml(xDoc.SelectNodes("//."));
var ms = (MemoryStream) transform.GetOutput(typeof (Stream));
ms.Flush();
File.WriteAllBytes(@"child1.xml", ms.ToArray());

In child1.xml I have:

<Root xmlns:test="http://www.test.com/xades#" Attr="root">&#xD;
  <Child1 Attribute1="c1" Bttribute="c2" Cttribute="c3">&#xD;
    <child11 Attribute11="c11">Element11</child11>&#xD;
  </Child1>&#xD;
  <Child2 Attribute2="c2">&#xD;
    <child21 Attribute21="c21">Element21</child21>&#xD;
    <child22 Attribute22="c22">Element22</child22>&#xD;
  </Child2>&#xD;
  <Child3 Attribute3="c3">&#xD;
    <child31 Attribute32="c31">&#xD;
      <child311 Attribute311="c311">Element311</child311>&#xD;
    </child31>&#xD;
  </Child3>&#xD;
</Root>

Hope it helped. Tobias




回答3:


Have you checked MSDN: http://msdn.microsoft.com/en-us/library/fzh48tx1.aspx Sample on their page has a comment which says that "This transform does not contain inner XML elements" - meaning a known issue.

You could try different XPaths like //child1/* or //child1|//child1/* or //child1// or explicit nodes() selection (check full XPath syntax at http://msdn.microsoft.com/en-us/library/ms256471.aspx) but you are in a gray zone - gambling with a bug.

So, in your ms2.xml is the actual output you wanted you'll just have to do that intermediary serialization for the time being.

Also fire up Reflector and take a look - the class is probably not terribly complicated.




回答4:


A separate answer on how to deal with the fact that XmlDocument doesn't distinguish U+000D in the source (should not be preserved) from explicit references such as &#xd; in the source (should be preserved).

Instead of:

using (FileStream fs = new FileStream(path, FileMode.Open))
{
    xDoc.Load(fs);
}

We first create a newline-cleaning TextReader:

private class LineCleaningTextReader : TextReader
{
  private readonly TextReader _src;
  public LineCleaningTextReader(TextReader src)
  {
    _src = src;
  }
  public override int Read()
  {
    int r = _src.Read();
    switch(r)
    {
      case 0xD:// \r
        switch(_src.Peek())
        {
          case 0xA: case 0x85: // \n or NEL char
            _src.Read();
            break;
        }
        return 0xA;
      case 0x85://NEL
        return 0xA;
      default:
        return r;
    }
  }
}

We then use this in Loading the xDoc:

using (FileStream fs = new FileStream(path, FileMode.Open))
{
  using(TextReader tr = new StreamReader(fs))
    xDoc.Load(new LineCleaningTextReader(tr));
}

This then normalises newlines prior to processing, but leaves explicit alone.



来源:https://stackoverflow.com/questions/3362454/how-to-use-xmldsigc14ntransform-class-in-c-sharp

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!