问题
I would like to find all occurrences of a substring in a NSString, and iterate one by one to do some changes to that NSString. How should I do it?
回答1:
How about
// find first occurrence of search string in source string
NSRange range = [sourceString rangeOfString:@"searchString"];
while(range.location != NSNotFound)
{
// build a new string with your changed values
range = [sourceString rangeOfString:@"searchString" options:0 range:NSMakeRange(range.location + 1, [sourceString length] - range.location - 1)];
}
Or just
[sourceString stringByReplacingOccurrencesOfString:searchString withString:targetString];
if you want to change the searchString to the same value everywhere in the source string.
回答2:
I would go with something like this:
// Setup what you're searching and what you want to find
NSString *string = @"abcabcabcabc";
NSString *toFind = @"abc";
// Initialise the searching range to the whole string
NSRange searchRange = NSMakeRange(0, [string length]);
do {
// Search for next occurrence
NSRange range = [string rangeOfString:toFind options:0 range:searchRange];
if (range.location != NSNotFound) {
// If found, range contains the range of the current iteration
// NOW DO SOMETHING WITH THE STRING / RANGE
// Reset search range for next attempt to start after the current found range
searchRange.location = range.location + range.length;
searchRange.length = [string length] - searchRange.location;
} else {
// If we didn't find it, we have no more occurrences
break;
}
} while (1);
回答3:
If you want to do changes, you could use:
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
but if that doesn't fit your needs try this:
- (void)enumerateSubstringsInRange:(NSRange)range options:(NSStringEnumerationOptions)opts usingBlock:(void (^)(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop))block
回答4:
You might want to have a look on NSString class Documentation.
Finding Characters and Substrings
– rangeOfCharacterFromSet:
– rangeOfCharacterFromSet:options:
– rangeOfCharacterFromSet:options:range:
– rangeOfString:
– rangeOfString:options:
– rangeOfString:options:range:
– rangeOfString:options:range:locale:
– enumerateLinesUsingBlock:
– enumerateSubstringsInRange:options:usingBlock:
Dividing Strings
– componentsSeparatedByString:
– componentsSeparatedByCharactersInSet:
– stringByTrimmingCharactersInSet:
– substringFromIndex:
– substringWithRange:
– substringToIndex:
回答5:
Expanding on @TheEye's answer, I cooked this up:
@interface NSString (EnumerateOccurancesOfString)
- (void)enumerateOccurancesOfString:(NSString *)string usingBlock:(void (^)(NSRange substringRange, BOOL *stop))block;
@end
-
@implementation NSString (EnumerateOccurancesOfString)
- (void)enumerateOccurancesOfString:(NSString *)string usingBlock:(void (^)(NSRange range, BOOL * _Nonnull stop))block {
NSParameterAssert(block);
NSRange range = [self localizedStandardRangeOfString:string];
if (range.location == NSNotFound) return;
// Iterate all occurances of 'string'
while (range.location != NSNotFound)
{
BOOL stop = NO;
block(range, &stop);
if (stop) {
break;
}
// Continue the iteration
NSRange nextRange = NSMakeRange(range.location + 1, self.length - range.location - 1);
range = [self rangeOfString:string options:(NSStringCompareOptions)0 range:nextRange locale:[NSLocale currentLocale]]; // Will this sometimes conflict with the initial range obtained with -localizedStandardRangeOfString:?
}
}
@end
来源:https://stackoverflow.com/questions/9615845/iphone-iterate-over-substring-occurrences-of-a-nsstring