WPF ToggleButton incorrect render behavior

非 Y 不嫁゛ 提交于 2019-12-06 02:09:59

That's my solution for the problem, here is the video, the usage:

<StackPanel>
    <ToggleButton x:Name="MyToggleButton" Content="MyToggleButton" Checked="MyToggleButton_Checked"
                    l:CorrectToggleButtonCheckedEnableBehavior.IsActive="True"/>
    <Button Name="EnableButton" Content="Enable" Click="EnableButton_Click"/>
</StackPanel>

and the attached behavior source code:

public static class CorrectToggleButtonCheckedEnableBehavior
{
    public static bool GetIsActive(ToggleButton toggleButton)
    {
        return (bool)toggleButton.GetValue(IsActiveProperty);
    }

    public static void SetIsActive(ToggleButton toggleButton, bool value)
    {
        toggleButton.SetValue(IsActiveProperty, value);
    }

    public static readonly DependencyProperty IsActiveProperty =
        DependencyProperty.RegisterAttached("IsActive", typeof(bool), typeof(CorrectToggleButtonCheckedEnableBehavior),
        new UIPropertyMetadata(false, OnIsActiveChanged));

    static void OnIsActiveChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
    {
        var toggleButton = (ToggleButton)d;

        if (GetIsActive(toggleButton))
        {
            toggleButton.IsEnabledChanged += new DependencyPropertyChangedEventHandler(ToggleButton_IsEnabledChanged);
        }
        else
        {
            toggleButton.IsEnabledChanged -= new DependencyPropertyChangedEventHandler(ToggleButton_IsEnabledChanged);
        }
    }

    static void ToggleButton_IsEnabledChanged(object sender, DependencyPropertyChangedEventArgs e)
    {
        var toggleButton = (ToggleButton)sender;

        if (toggleButton.IsEnabled && (toggleButton.IsChecked ?? false))
        {
            Invalidate(toggleButton);
        }
    }

    static void Invalidate(ToggleButton toggleButton)
    {
        var controlTemplate = toggleButton.Template;
        toggleButton.Template = null;
        toggleButton.Template = controlTemplate;
    }
}
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