Upload image using jquery

问题

I have a working php code to upload image in the database. Is it Possible to transform it to jquery? If so, what do I need to do? I am new to jquery btw. Thanks

This code works just fine. But I need to do it in jquery.

<form action = 'upload.php' method = 'post' enctype="multipart/form-data">

    <input type="file" name="image" > <br>
    <input type= 'submit' value = 'Add' id = 'Add' name = 'Add'>

</form> 


<?php   
    if(isset($_FILES['image']))
    {
    $target_Path = "images/";
    $target_Path = $target_Path.basename($_FILES['image']['name'] );
    move_uploaded_file( $_FILES['image']['tmp_name'], $target_Path );

    $name = $_FILES['image']['name'];
    }
    if(isset($_POST['Add']))
    {

        if($_POST["Add"] == "Add") 
        {
        $add = "Insert Into img(path) Values('$name')";
        $up = mysql_query($add);

            $status = "Upload success!";
            print '<script type="text/javascript">'; 
            print 'alert(" '.$status.' ")'; 
            print '</script>';                  
        }
    }

回答1:

<form action='upload.php' method='post' enctype="multipart/form-data" id="formupload">
    <input type="file" name="image"/> <br>
    <input type='submit' value='Add' id='Add' name='Add/>
</form>

You need to first setup a callback for the submit event of the form.
```
$("#formupload").on("submit", upload_image);
```
- JQuery selectors work a lot like CSS; $("#formupload") selects the element whose id is formupload.
- on is used to register a handler for an event.
- Here, we are setting up a handler(the upload_image function) for the submit event of the element whose id is formupload.
Make an AJAX call to the php script.
```
function upload_image(event){

    event = event || window.event;

    // Prevent the default form action i.e. loading of a new page
    if(event.preventDefault){ // W3C Variant
        event.preventDefault();
    }
    else{ // IE < 9
        event.returnValue = false;
    }

    $.ajax({
        url: "upload.php",
        type: "POST",
        data: new FormData($('#formupload')[0]), 

        success : function(data){
            // Show success message
        },
        enctype: 'multipart/form-data',
        processData: false,
        contentType: false,
        cache: false
    });
}
```
- You can prevent the default action of form submission, which is to load the POST response, which is what the first few lines of the function is doing.
- An AJAX call is made using $.ajax which is the jQuery utility for performing an AJAX call.
- The url property is to be filled by that of your PHP script.
- Since it is a file upload, specify the HTTP method as POST.
- The data property is the payload of the POST request, which is the content of the file you are trying to upload.
- You can specify the success callback using the success property, which is the function that will be called on completion of the file upload.

回答2:

You can make an ajax call instead to submit a form. You can use something like this as well:

https://blueimp.github.io/jQuery-File-Upload/

Although, you still need to have your php code in order to store the file in your server

来源：https://stackoverflow.com/questions/29791355/upload-image-using-jquery

标签

php

jquery

image-uploading