NetLogo Efficient way to create fixed number of links

问题

I have about 5000 agents (people) in my model. I want to give them an arbitrary number of friends and have reciprocal but random pairing. So if person A chooses person B then person B also chooses person A. My code works fine, but is fairly slow. I will likely want to increase both the number of friends and the number of people in the future. Any quicker suggestions?

ask people
[ let new-links friends - count my-links
  if new-links > 0
  [ let candidates other people with [ count my-links < friends ]
    create-links-with n-of min (list new-links count candidates) candidates
    [ hide-link ]
  ]
]

Note that friends is a global variable in the above code, but my eventual code will probably generalise to have wanted-number-of-friends as an attribute of people.

EDITED Added if new-links > 0 condition so that the nested ask is avoided when no candidates need to be found. This improved speed but still not really scaleable.

回答1:

Great question. This is actually quite challenging to optimize. The problematic line is:

let candidates other people with [ count my-links < friends ]

This is slow because it has every agent checking with every other agent. With 5000 agents, that's 25,000,000 checks! Unfortunately, there isn't really a good way to optimize this particular line without some fancy data structures.

Fortunately, there is a solution that generalizes really well to generating any degree distribution in the network (which it sounds like that's what you ultimately want). Unfortunately, the solution doesn't translate super well to NetLogo. Here it is though:

  let pairs [] ;; pairs will hold a pairs of turtles to be linked
  while [ pairs = [] ] [ ;; we might mess up creating these pairs (by making self loops), so we might need to try a couple of times
    let half-pairs reduce sentence [ n-values friends [ self ] ] of turtles ;; create a big list where each turtle appears once for each friend it wants to have
    set pairs (map list half-pairs shuffle half-pairs) ;; pair off the items of half-pairs with a randomized version of half-pairs, so we end up with a list like: [[ turtle 0 turtle 5 ] [ turtle 0 turtle 376 ] ... [ turtle 1 turtle 18 ]]
    ;; make sure that no turtle is paired with itself
    if not empty? filter [ first ? = last ? ] pairs [
      set pairs []
    ]
  ]
  ;; now that we have pairs that we know work, create the links
  foreach pairs [
    ask first ? [
      create-link-with last ?
    ]
  ]

It doesn't matter if friends here is a global or a turtle variable. The amount of time this takes depends on the number of times that it needs to try making pairs, which is random. Experimenting, I found that it was usually about 3 seconds with 5000 agents, each with degree 5. This is compared to about 60 seconds on my machine with your original way of doing this (which, for what it's worth, is the way I would recommend when using fewer agents).

回答2:

After debugging (see NetLogo Efficiently create network with arbitrary degree distribution), the following version is relatively efficient. It needs a global variable (called lonely below) to store the agentset of turtles that still need links. Removing individual turtles is more efficient than the nested process to create the candidate set each time.

  ask turtles
  [ set lonely other lonely
    let new-links nFriends - count my-links
    if new-links > 0
    [ let chosen n-of min (list new-links count lonely) lonely
      create-links-with chosen [ hide-link ]
      ask chosen [ if count my-links = nFriends [ set lonely other lonely ] ]
    ]
  ]

来源：https://stackoverflow.com/questions/32967388/netlogo-efficient-way-to-create-fixed-number-of-links

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