Multiplying __int64's

有些话、适合烂在心里 提交于 2019-12-05 13:22:41

not assuming a and b are positive:

__int64 a,b;
//...
__int64  tmp_result = abs(a) * abs(b) ;
if (
    ( a && b ) &&
    (
     ( tmp_result < abs(a) || tmp_result < abs(b) ) ||
     ( tmp_result / abs(a) != abs(b)) ||
     ( a == TYPE_MIN && b != 1) ||
     ( b == TYPE_MIN && a != 1)
    )
   )
   std::cout << "overflow";
__int64 result = a * b;

EDIT: Adding corner cases to code.

EDIT: In my opinion just ( a && a * b / a != b) is enough.

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