问题
I am using font awesome icons and I need to have a disabled state of the icons. is there any way to do this. I am also using bootstrap.
This is how I am using icons.
<i class="fa fa-slack"><i/>
I just need the icon to look like grayed out.
回答1:
Write a custom class for disabled
Something like
.fa-disabled {
opacity: 0.6;
cursor: not-allowed;
}
Adding cursor type is important for users experience.
回答2:
You could define your "Bootstrap-like" disabled
class
.fa.disabled,
.fa[disabled],
.disabled > .fa,
[disabled] > .fa {
opacity: 0.5;
/*optional*/ cursor: not-allowed;
/*optional*/ pointer-events: none;
}
and then use it like
<i class="fa fa-slack disabled"></i> <!-- or -->
<i class="fa fa-slack" disabled></i> <!-- or -->
<a class="btn btn-primary disabled"><i class="fa fa-slack"></i></a> <!-- or -->
<a class="btn btn-primary" disabled><i class="fa fa-slack"></i></a>
回答3:
The basic idea is just to color its style
<link href="https://maxcdn.bootstrapcdn.com/font-awesome/4.6.3/css/font-awesome.min.css" rel="stylesheet"/>
<div>Disabled <i class="fa fa-slack" style="color: grey"></i></div>
<div>Enabled <i class="fa fa-slack"></i></div>
回答4:
You can decrease the opacity and disable the pointer events:
.disabled-button{
opacity: 0.5;
pointer-events: none;
}
来源:https://stackoverflow.com/questions/38781104/how-to-create-disabled-state-of-the-font-awesome-icons