System.TypeInitializationException

拈花ヽ惹草 提交于 2019-12-05 11:28:43

Your test calls Helper.OpenForm() and as you have no static constructor, the only thing I can see that would cause the exception to be thrown is:

private static MainForm f =  new MainForm();

Therefore something in the constructor for MainForm is likely throwing an exception. Put a breakpoint on the first line of the constructor for MainForm and step through until you see where the exception is thrown.

Alternatively you might find it easier to determine what the problem is, at least initially, by writing a new test you can step through that calls new MainForm() directly:

[TestMethod]
public void Validate_OpenInfopathInFormControl()
{
    var form = new MainForm();
}

Put a breakpoint on the only line of the test and step into the constructor to determine why it's throwing a NullReferenceException.

The type initialiser, in this case, is where your static fields are initialised; That is, these two lines:

private static MainForm f =  new MainForm();
private static bool _isOpen = false;

The initialisation of a bool isn't going to cause any kind of exception, so it's highly likely that the source of the error is in the MainForm constructor.

Does the TypeInitializationException object contain any inner exceptions? If so, they should give you more info about the real cause of the error.

You have an error in your static constructor (they are called Type Initializers). The inner exception is a NullReference exception. If you post your code we might be able to help you.

The rules determine when type initializers get run are complex, but it is guaranteed that they are run before you access the type in any way. It might not be directly obvious to you that you have a type initializer on your Helper class because you might use implicit initialization:

public class Helper
{   
    static int i = 10; // This assignment will end up in a type initializer
    static Helper()
    {
        // Explicit type initializer
        // The compiler will make sure both, implicit and explicit initializations are run
    }
}
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