jQuery Offset returns negative value

孤人 提交于 2019-12-05 08:33:19

http://jsfiddle.net/Ldfmvwr9/3/

Try it

topValue=$('#container').scrollTop() + $("#"+parseInt(userPageNum)).offset().top - $("#"+parseInt(userPageNum)).height() / 2;

Late answer, in case it will help someone:

Just use dom offsetTop property. That will be a correct position despite whatever scrolling has happened before.

$( something )[0].offsetTop; 
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