I tried a couple of hours to find a pure sed solution for this question. Obviously, unfortunately I had not succeed. A really tricky question.
Examples (from the awk question):
- input:
aaa 111 aaa 222 aaa 333 bbb 444 bbb 555 ccc 666
- output:
aaa 111,222,333 bbb 444,555 ccc 666
- input
APM00065101435 189 APM00065101435 190 APM00065101435 191 APM00065101435 390 190104555 00C7 190104555 00D1 190104555 00E1 190104555 0454 190104555 0462 APM00065101435 391 APM00065101435 392
- output
APM00065101435 189,190,191,390 190104555 00C7,00D1,00E1,0454,0462 APM00065101435 391,392
What have I tried? Some of my non working examples:
sed -nr '1{h;b};H;x;/(\S+).*\n\1.*\'/M{x;b};s/.*\'//m;s/\n\S*\s*/,/g;s/,$//;p' file
sed -nr '1{h;b};H;x;h;s/(\S+).*\n(\S+).*\'/\1\n\2/m;/(\S+)\n\1\'/M{$!b;g;bk};g;s/\n.*\'//m;:k;s/^\S+\s//2mg;s/\n/,/g;p;x;s/.*\n//;h;$l' file2
sed -nr 'H;g;s/(\S+)\s.*/\1/gm;/(\S+)\n\1\'/M{$!b;g;bk};g;1d;s/\n.*\'//m;:k;s/\n\S+\s/,/2g;s/\n//;p;g;s/\n.*(\n.*)$/\1/;h' file2
Thanks for reading this.
This might work for you (GNU sed):
sed -r ':a;$!N;s/^(([^ ]+ ).*)\n\2/\1,/;ta;P;D' file
or if you prefer:
sed -r ':a;$!N;s/^((\S+\s).*)\n\2/\1,/;ta;P;D' file
This reads 2 lines into the pattern space, compares the beginning of each line and if they are the same replaces the beginning of the second line that matches the first with a comma and repeats. If the lines do not match it prints out the first line.
来源：https://stackoverflow.com/questions/17414805/complex-transposing-of-columns-with-pure-sed