Android: How to initialize a variable of type “Location” (other than making it equal to null)

痞子三分冷 提交于 2019-12-05 08:20:22

问题


I'm looking to test some code I've written and to do so I need to construct a variable of type Location and to give it a long / lat value but I'm unsure how I would do so. Any ideas?


回答1:


The API documentation is quite clear on this. First create a new Location instance:

Location loc = new Location("dummyprovider");

And then use the setter methods to set the location parameters you need, e.g.:

loc.setLatitude(20.3);
loc.setLongitude(52.6);



回答2:


Location object = new Location("service Provider");

it will create an object of Type Location that contains the initial Latitude and Longitude at location '0' to get the initial values use

double lat = object.getLatitude();
double lng = object.getLongitude();



回答3:


You can write a method:

Location createNewLocation(double longitude, double latitude) {
    Location location = new Location("dummyprovider");
    location.setLongitude(longitude);
    location.setLatitude(latitude);
    return location;
}

And then call it:

Location myLoc = createNewLocation(dLong, dLati);

Or you can use string with Double.parse():

Location myLoc = createNewLocation(Double.parse("s.Long"), Double.parse("s.Lati"));



回答4:


In Kotlin using LocationManager class you can pass the required location provider like:

val location = Location(LocationManager.NETWORK_PROVIDER) // OR GPS_PROVIDER based on the requirement
location.latitude = 42.125
location.longitude = 55.123


来源:https://stackoverflow.com/questions/2985302/android-how-to-initialize-a-variable-of-type-location-other-than-making-it-e

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!