How can I emit a dynamic method returning a ref?

冷暖自知 提交于 2019-12-05 06:58:50

I don't know why this limitation exists for DynamicMethod, but the following worked for me. One difference is that we are defining our own dynamic assembly by hand. Another difference is that since this is separate assembly, Widget needs to be public (or if you name the dynamic assembly appropriately you could use InternalsVisibleTo on the parent assembly).

static void Main(string[] args)
{
    var widget = new Widget();
    GetLengthMeasurer()(widget) = 7;
    Console.WriteLine(widget.Length);
}

private static WidgetMeasurer GetLengthMeasurer()
{
    var fieldInfo = typeof(Widget).GetField("Length");
    var asmName = new AssemblyName("WidgetDynamicAssembly." + Guid.NewGuid().ToString());
    var asmBuilder = AppDomain.CurrentDomain.DefineDynamicAssembly(asmName, AssemblyBuilderAccess.RunAndCollect);
    var moduleBuilder = asmBuilder.DefineDynamicModule("<Module>");
    var typeBuilder = moduleBuilder.DefineType("WidgetHelper");
    var methodBuilder = typeBuilder.DefineMethod("GetLength", MethodAttributes.Static | MethodAttributes.Public, typeof(int).MakeByRefType(), new[] { typeof(Widget) });
    var ilGen = methodBuilder.GetILGenerator();
    ilGen.Emit(OpCodes.Ldarg_0);
    ilGen.Emit(OpCodes.Ldflda, fieldInfo);
    ilGen.Emit(OpCodes.Ret);
    var type = typeBuilder.CreateType();
    var mi = type.GetMethod(methodBuilder.Name);
    var del = (WidgetMeasurer)mi.CreateDelegate(typeof(WidgetMeasurer));
    return del;
}

Output:

7

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