Get the name of a JObject in Json.Net

邮差的信 提交于 2019-12-05 06:37:45

In JSON, objects themselves do not have names. An object is just a container for a collection of name-value pairs, beginning and ending with curly braces. So what you have above is a fragment of a larger body of JSON. There must be an outer object to contain it. That outer object has a property with a name of Info, and the value of that property is the object you are referring to.

{
    "Info":
    {
        "View":"A",
        "Product":"B",
        "Offer":"Offer1",
        "Demo":"body {background-color:red;} #box {border:dotted 50px red;}",
        "Log":false
    }
}

In Json.Net, a JObject models a JSON object, and a JProperty models a name-value pair contained within a JObject. Each JObject has a collection of JProperties which are its children, while each JProperty has a Name and a single child, its Value.

So, assuming you have a reference to the innermost JObject (containing the View, Product and Offer properties), you can get the name of its containing JProperty like this:

JProperty parentProp = (JProperty)jObject.Parent;
string name = parentProp.Name;  // "Info"
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