Using Boost Tokenizer escaped_list_separator with different parameters

问题

Hello i been trying to get a tokenizer to work using the boost library tokenizer class. I found this tutorial on the boost documentation:

http://www.boost.org/doc/libs/1 _36 _0/libs/tokenizer/escaped _list _separator.htm

problem is i cant get the argument's to escaped _list _separator("","","");

but if i modify the boost/tokenizer.hpp file it work's. but that's not and ideal solution was wondering if there's anything i am missing to get diferent arguments into the escaped _list _separator.

i want to make it split on spaces with " and ' for escaping and with no escape character inside the quoted string.

this is used for a argument parsing system in a ingame console system.


include <iostream>
include <boost/tokenizer.hpp>
include <string>

int main()
{
    using namespace std;
    using namespace boost;
    string s = "exec script1 \"script argument number one\"";
    string separator1("");//dont let quoted arguments escape themselves
    string separator2(" ");//split on spaces
    string separator3("\"\'");//let it have quoted arguments
    tokenizer<escaped_list_separator<char>(separator1,separator2,separator3)> tok(s);
    for(tokenizer<escaped_list_separator<char>(separator1,separator2,separator3)>::iterator beg=tok.begin(); beg!=tok.end();++beg)
    {
    cout << *beg << "\n";
    }
}

the error from visual studio 2005 is error C2974: 'boost::tokenizer' : invalid template argument for 'TokenizerFunc', type expected

EDIT: This question was awnsered by ferrucio and explained by peter thank's everybody.

回答1:

try this:

#include <iostream>
#include <boost/tokenizer.hpp>
#include <string>

int main()
{
    using namespace std;
    using namespace boost;
    string s = "exec script1 \"script argument number one\"";
    string separator1("");//dont let quoted arguments escape themselves
    string separator2(" ");//split on spaces
    string separator3("\"\'");//let it have quoted arguments

    escaped_list_separator<char> els(separator1,separator2,separator3);
    tokenizer<escaped_list_separator<char>> tok(s, els);

    for(tokenizer<escaped_list_separator<char>>::iterator beg=tok.begin(); beg!=tok.end();++beg)
    {
        cout << *beg << "\n";
    }
}

回答2:

It seems like you're declaring your tokenizer type incorrectly.

typedef boost::tokenizer< boost::escaped_list_separator<char> > Tokenizer;
boost::escaped_list_separator<char> Separator( '\\', ' ', '\"' );
Tokenizer tok( s, Separator );

for( Tokenizer::iterator iter = tok.begin(); iter != tok.end(); ++iter )
{ cout << *iter << "\n"; }

You want to make a boost::tokenizer< boost::escaped_list_separator< char > > typed object with a boost::escaped_list_separator< char > separator object as its TokenizerFunc.

回答3:

A relevant point yet not the answer for this is that if user want to output a double quote in the result, the embedded quote ("") described in the Wikipedia (like here) should be replaced with a string of (\\\"), where \\ means a escape char and \" means the quote mark. In this way, the quote mark will be displayed in the output result. The following code snippet is an example.

typedef boost::escaped_list_separator<char> std_token;
typedef boost::tokenizer<boost::escaped_list_separator<char>> tokenizer;

std_token a_token( "\\", ",", "\"" );
std::string s = "\"Boost,\\\" C++ Libraries\" ";
tokenizer tok{ s, a_token };
for ( const auto &t : tok )
    std::cout << t << '\n';

This is a typical output for this

来源：https://stackoverflow.com/questions/541561/using-boost-tokenizer-escaped-list-separator-with-different-parameters

标签

c++

string

boost

tokenize