Convert HttpContent into byte[]

Question

I am currently working on a c# web API. For a specific call I need to send 2 images using an ajax call to the API, so that the API can save them as varbinary(max) in the database.

1. How do you extract an Image or byte[] from a HttpContent object?
2. How do I do this twice? Once for each image.

-

var authToken = $("#AuthToken").val();
var formData = new FormData($('form')[0]);
debugger;
$.ajax({
    url: "/api/obj/Create/", 
    headers: { "Authorization-Token": authToken },
    type: 'POST',
    xhr: function () { 
        var myXhr = $.ajaxSettings.xhr();
        return myXhr;
    },
    data: formData,
    cache: false,
    contentType: false,
    processData: false
});

-

public async Task<int> Create(HttpContent content)
{
    if (!content.IsMimeMultipartContent())
    {
        throw new UnsupportedMediaTypeException("MIME Multipart Content is not supported");
    }

    return 3;
}

Answer 1

HttpContent has a Async method which return ByteArray i.e (Task of ByteArray)

 Byte[] byteArray = await Content.ReadAsByteArrayAsync();

You can run the method synchronously

Byte[] byteArray = Content.ReadAsByteArrayAsync().Result;

Answer 2

if (!content.IsMimeMultipartContent())
{
    throw new UnsupportedMediaTypeException("MIME Multipart Content is not supported");
}

var uploadPath = **whatever**;
if (!Directory.Exists(uploadPath))
{
    Directory.CreateDirectory(uploadPath);
}

var provider = new MultipartFormDataStreamProvider(uploadPath);
await content.ReadAsMultipartAsync(provider);

return File.ReadAllBytes(provider.FileData[0].LocalFileName);

Answer 3

Please look at CopyToAsync(Stream, TransportContext) method exposed by ByteArrayContent Class. [msdn link]

Answer 4

You can use HttpContent.ReadAsByteArrayAsync:

byte[] bytes = await response.Content.ReadAsByteArrayAsync();

Or, you can read the content with HttpContent.ReadAsStreamAsync and extract to a byte[] from there:

var stream = response.Content.ReadAsStreamAsync();
using (var memoryStream = new MemoryStream())
{
      await stream.CopyToAsync(stream);
      return memoryStream.ToArray();
}