Cron expression to run job twice a day at different time?

Question

I have one job that needs to be execute twice a day at different time . e.g. 10:00 and 15:30. How can i achieve this ?

I am confuse because minute is different for both the time. For 11:00 and 15:00 its easy because for both the times, minute portion is same, but for the different minute portion is it feasible with cron ?

Thanks in Advance and apologies for silly question.

Answer 1

Try following which you will get closest in one expression

0 0 10,15/12 * * ?

this will run 10:00 and 15:00.

Answer 2

You can set values for each job:

0 10 * * * job

30 15 * * * job

Here is more info:

*    *    *    *    *  command to be executed
┬    ┬    ┬    ┬    ┬
│    │    │    │    │
│    │    │    │    │
│    │    │    │    └───── day of week (0 - 7) (0 or 7 are Sunday, or    use names)
│    │    │    └────────── month (1 - 12)
│    │    └─────────────── day of month (1 - 31)
│    └──────────────────── hour (0 - 23)
└───────────────────────── min (0 - 59)

Wikipage about cron https://en.wikipedia.org/wiki/Cron