taskkill to differentiate 2 images by path

Question

How to kill a process by name and orginiated from a particular path using taskkill?

taskkill /F /IM

certainly it cant differentiate 2 process started from two different locations C:\Dir1 and C:\Dir2

Does tasklist has any switch to get the path name

Answer 1

taskkill cannot do it. But you could use PowerShell if it's an option:

(Get-WmiObject Win32_Process | Where-Object { $_.Path.StartsWith('C:\Dir1') }).Terminate()

Answer 2

Based on Joey's answer:

wmic Path win32_process Where "CommandLine Like '%-jar selenium-server.jar%'" Call Terminate

This way I avoid NullReferenceException when Path is null (don't know why) and does not need PowerShell.

Ref: https://superuser.com/questions/52159/kill-a-process-with-a-specific-command-line-from-command-line

Answer 3

Use the following command (it works even without powershell):

wmic process where ExecutablePath='C:\\Dir1\\image.exe' delete

NOTE: ExecutablePath is accessable for all processes only if you run wmic as administrator on Windows 8

Answer 4

Your case seems to be when you have custom services with same process name installed on the machine from different paths. If this is indeed the scenario, you probably have different Service Names which can be used as an additional filter.

See Syntax:

taskkill /S {REPLACE_WITH_SERVER_IP_OR_NAME} /F /FI "IMAGENAME eq {REPLACE_WITH_PROCESS_NAME}" /FI "SERVICES eq {REPLACE_WITH_SERVICENAME}"

See Example:

taskkill /S 10.10.1.1 /F /FI "IMAGENAME eq tomcat7.exe" /FI "SERVICES eq tomcatServiceEngine"

For list of all available filters, please visit taskkill command