Pass List to method without modifying original list

问题

Is this the only way of passing a List to a method and editing that List, without modifying the original List?

class CopyTest1
{
    List<int> _myList = new List<int>();
    public CopyTest1(List<int> l)
    {
        foreach (int num in l)
        {
            _myList.Add(num);
        }
        _myList.RemoveAt(0); // no effect on original List
    }
}

回答1:

duplicate the list:

_myLocalList = new List<int>(_myList);

and perform the operations on the local list.

回答2:

Use AsReadOnly for this:

class CopyTest1
{
    List<int> _myList = new List<int>();
    public CopyTest1(IList<int> l)
    {
        foreach (int num in l)
        {
            _myList.Add(num);
        }
        _myList.RemoveAt(0); // no effect on original List
    }
}

And call it via CopyTest1(yourList.AsReadOnly()) .

回答3:

There is another way. You can use the copy constructor of List<T>:

List<int> _myList;
public CopyTest1(List<int> l)
{
    _myList = new List<int>(l);
}

回答4:

Clone objects in the list to other list and work on this copy

static class Extensions
{
        public static IList<T> Clone<T>(this IList<T> listToClone) where T: ICloneable
        {
                return listToClone.Select(item => (T)item.Clone()).ToList();
        }
}

回答5:

When you pass a list to a method you pass a pointer to said list, that's why your changing the 'original' list when you modify it inside your method. If you instead want to modify a copy of the list you just need to make one. In the code that calls CopyTest1 you can create a new list based on your original list:

public void CallsCopyTest1()
{
    var originalList = new List<int>();
    var newList = new List<int>(originalList);
    var copyTest = new CopyTest1(newList); //Modifies newList not originalList
}
class CopyTest1
{
    List<int> _myList = new List<int>();
    public CopyTest1(List<int> l)
    {
        foreach (int num in l)
        {
            _myList.Add(num);
        }
        _myList.RemoveAt(0); // no effect on original List
    }
}

回答6:

You can pass an object by reference doing the following:

public static void ReferenceMethod(ref List<T> myParam) {
    ...
}

EDIT: The question has now been clarified, the OP was after a way not to alter the original list.

来源：https://stackoverflow.com/questions/7712842/pass-list-to-method-without-modifying-original-list

标签

list

pass-by-reference