what does it mean “(include_path='.:/usr/share/pear:/usr/share/php')”?

Question

I have file structure on EC2 like : but facing some file referencing problem.

index.php
-db
  -config.php
-cron
  -cron1.php

I have tried file referencing as:

`require_once (dirname(__FILE__).'/db/config.php');`
`require_once (($_SERVER['DOCUMENT_ROOT']).'/db/config.php');`

but cron doesn't run.it gives error in mail as

`PHP Warning:  require_once(/db/config.php): failed to open stream: No such file or directory in /var/www/html/cron/cron1.php on line 3

Warning: require_once(/db/config.php): failed to open stream: No such file or directory in /var/www/html/cron/cron1.php on line 3

PHP Fatal error:  require_once(): Failed opening required '/db/config.php' (include_path='.:/usr/share/pear:/usr/share/php') in /var/www/html/cron/cron1.php on line 3

Fatal error: require_once(): Failed opening required '/db/config.php' (include_path='.:/usr/share/pear:/usr/share/php') in /var/www/html/cron/cron1.php on line 3`

Answer 1

If you look at the PHP constant PATH_SEPARATOR, you will see it being ":" for you.

If you break apart your string ".:/usr/share/pear:/usr/share/php" using that character, you will get 3 parts

• . (this means the current directory your code is in)
• /usr/share/pear
• /usr/share/ph

Any attempts to include()/require() things, will look in these directories, in this order.

It is showing you that in the error message to let you know where it could NOT find the file you were trying to require()

For your first require, if that is being included from your index.php, then you dont need the dir stuff, just do:

require_once ( 'db/config.php');

Answer 2

Solution to the problem

as mentioned by Uberfuzzy [ real cause of problem ]

If you look at the PHP constant [PATH_SEPARATOR][1], you will see it being ":" for you.

If you break apart your string ".:/usr/share/pear:/usr/share/php" using that character, you will get 3 parts

• . (this means the current directory your code is in)
• /usr/share/pear
• /usr/share/ph

Any attempts to include()/require() things, will look in these directories, in this order.

It is showing you that in the error message to let you know where it could NOT find the file you were trying to require()

That was the cause of error.

Now coming to solution

1. Step 1 : Find you php.ini file using command php --ini ( in my case : /etc/php5/cli/php.ini )
2. Step 2 : find include_path in vi using esc then press /include_path then enter
3. Step 3 : uncomment that line if commented and include your server directory, your path should look like this include_path = ".:/usr/share/php:/var/www/<directory>/"
4. Step 4 : Restart apache sudo service apache2 restart

This is it. Hope it helps.

Answer 3

Actually, the solutions is to open the php.ini file edit the include_path line and either completely change it to

include_path='.:/usr/share/php:/usr/share/pear' 

or append the

'.:/usr/share/php:/usr/share/pear' 

to the current value of include_path.

It is further explained in : http://pear.php.net/manual/en/installation.checking.php#installation.checking.cli.phpdir

Answer 4

I had a similar problem. Just to help out someone with the same issue:

My error was the user file attribute for the files in /var/www. After changing them back to the user "www-data", the problem was gone.

Answer 5

Thats just the directories showing you where PHP was looking for your file. Make sure that cron1.php exists where you think it does. And make sure you know where dirname(__FILE__) and $_SERVER['DOCUMENT_ROOT'] are pointing where you'd expect.

This value can be adjusted in your php.ini file.

Answer 6

I had the same error while including file from root of my project in codeigniter.I was using this in common.php of my project.

<?php include_once base_url().'csrf-magic-master/csrf-magic.php';  ?>

i changed it to

<?php include_once ('csrf-magic-master/csrf-magic.php');  ?>

Working fine now.