Angular2 or TypeScript Left padding a String with Zeros

Question

I have a number let say 9. But I need it as String "09".

I know i can write my own logic. But I am looking for a implicit util function which can pad it.

I am using angular2 with TypeScript. Looking for something like this.

Just Similar like java

String.format("%010d", Integer.parseInt(mystring));

Answer 1

You can create your own function for this. To format the number you will have to convert it to a string first.

function pad(num, size) {
    let s = num+"";
    while (s.length < size) s = "0" + s;
    return s;
}

TypeScript

pad(num:number, size:number): string {
    let s = num+"";
    while (s.length < size) s = "0" + s;
    return s;
}

Edit: There are a couple of better and more performant ways to do this. See the discussion in this Answer: https://stackoverflow.com/a/9744576/1734678 (I recommend reading most of the submitted answers if you got time)

Update: ECMAScript 2017 now has support for string padding

str.padStart(targetLength [, padString])
str.padEnd(targetLength [, padString])

Check https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart

Answer 2

Since Angular v4 there is DecimalPipe which let's easily add leading zeros: https://angular.io/api/common/DecimalPipe

In your html, you can use then something like:

{{ myNumber | number:'2.0' }}

Answer 3

You can use one of below templates in HTML

{{ ("00" + 9).slice(-2) }} // 09

Or

{{ 9 | number: '2.' }} // 09

Or in component ts code file

var x = ("00" + 9).slice(-2);

Answer 4

With the latest Typescript, you can do:

let myStr:string = padLeft('123', '0', 6);  // '000123'

padLeft(text:string, padChar:string, size:number): string {
    return (String(padChar).repeat(size) + text).substr( (size * -1), size) ;
}

Answer 5

public padIntegerLeftWithZeros(rawInteger: number, numberOfDigits: number): string {
    let paddedInteger: string = rawInteger + '';
    while (paddedInteger.length < numberOfDigits) {
        paddedInteger = '0' + paddedInteger;
    }
    return paddedInteger;
}

public zeroPadIntegerLeft3Digits(rawInteger: number): string {
    return this.padIntegerLeftWithZeros(rawInteger, 3);
}

Answer 6

You can create a Pipe for that

{{ID |LeftPadFilter: ID}}



import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
    name: 'LeftPadFilter',
    pure: false
})
export class LeftPadFilter implements PipeTransform {
    transform(item: string): string {
        return (String('0').repeat(2) + item).substr((2 * -1), 2);
    }
}